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Svetradugi [14.3K]
3 years ago
5

An election ballot asks voters to select three city commissioners from a group of six candidates, in how many ways can this be d

one?
Mathematics
1 answer:
slava [35]3 years ago
6 0
20 possibilities based on this as a combination not a permutation, 6 nCr 3 = 20
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Simplify.<br> -3(u + 3) + 4(4u + 2)
sergeinik [125]

Hello!

So, here you want to do the distributive property.

Start on the left side of the + sign...

-3*u = -3u

-3*3 = -9

So we now we have:

(-3u + -9) + 4(4u + 2)

Now we focus on the right side of the + sign...

4*4u=16u

4*2=8

So now we have:

(-3u + -9) + (16u + 8)

Now you want to combine like terms. Start by adding terms with the same variable. So, we need to add -3u and 16u

<em>-3u + 16u =</em> 13u

Now we have:

13u + -9 + 8

Now add the constants, -9 + 8

-9 + 8 = -1

So, the simplified expression would be:

13u - 1 or 13u + -1

6 0
3 years ago
Read 2 more answers
2x-4/5=4<br> plsss answer quick
nikdorinn [45]

Answer:

<h2>x = 12</h2>

Step-by-step explanation:

\frac{2x - 4}{5}  =4

First of all multiply through by 5 to eliminate the fraction

That's

5 \times  \frac{2x - 4}{5}  = 4 \times 5 \\ 2x - 4 = 20

Next using the addition property add 4 to both sides of the equation

We have

2x - 4 + 4 = 20 + 4 \\ 2x = 24

<u>Divide both sides by 2</u>

\frac{2x}{2}  =  \frac{24}{2}

We have the final answer as

<h3>x = 12</h3>

Hope this helps you

6 0
4 years ago
Read 2 more answers
Which of these ordered pairs is a solution to the inequality y &lt; x+1
Snowcat [4.5K]
We have that
<span>y < x+1

using a graph tool
see the attached figure

the answer is
</span><span>C. (15,0)</span>

3 0
3 years ago
A certain spinner has equally sized slices. The probability of landing on a red slice is 4/9. What are the odds in favor of land
Novosadov [1.4K]
There are 4 red slices out of 9 total. So there are 9-4 = 5 slices that are not red. The odds in favor of landing on red is 4:5

We basically write the number of ways to get what we want (4), followed by a colon, then the second number is the number of ways to get what we don't want (anything but red; 5 ways)

So that's why the answer is 4:5

-----------------------------------

Side Note -- If we want the odds against, we simply flip the ratio. The odds against would be 5:4 because there are 5 ways to lose and 4 ways to win. This is assuming that landing on red means you win.
4 0
4 years ago
Given cos(4x)+2<br><br> Find: Period, Shift, &amp; Range
Yuki888 [10]
\bf \qquad \qquad \qquad \qquad \textit{function transformations}&#10;\\ \quad \\&#10;% function transformations for trigonometric functions&#10;\begin{array}{rllll}&#10;% left side templates&#10;f(x)=&{{  A}}sin({{  B}}x+{{  C}})+{{  D}}&#10;\\\\&#10;f(x)=&{{  A}}cos({{  B}}x+{{  C}})+{{  D}}\\\\&#10;f(x)=&{{  A}}tan({{  B}}x+{{  C}})+{{  D}}&#10;&#10;\end{array}\qquad

\bf \begin{array}{llll}&#10;% right side info&#10;\bullet \textit{ stretches or shrinks}\\&#10;\quad \textit{horizontally by amplitude } |{{  A}}|\\\\&#10;\bullet \textit{ flips it upside-down if }{{  A}}\textit{ is negative}\\\\&#10;\bullet \textit{ horizontal shift by }\frac{{{  C}}}{{{  B}}}\\&#10;\qquad  if\ \frac{{{  C}}}{{{  B}}}\textit{ is negative, to the right}\\\\&#10;\qquad  if\ \frac{{{  C}}}{{{  B}}}\textit{ is positive, to the left}\\\\&#10;\end{array}

\bf \begin{array}{llll}&#10;&#10;&#10;\bullet \textit{vertical shift by }{{  D}}\\&#10;\qquad if\ {{  D}}\textit{ is negative, downwards}\\\\&#10;\qquad if\ {{  D}}\textit{ is positive, upwards}\\\\&#10;\bullet \textit{function period or frequency}\\&#10;\qquad \frac{2\pi }{{{  B}}}\ for\ cos(\theta),\ sin(\theta),\ sec(\theta),\ csc(\theta)\\\\&#10;\qquad \frac{\pi }{{{  B}}}\ for\ tan(\theta),\ cot(\theta)&#10;\end{array}

now, with that template in mind, let's see

\bf \begin{array}{llccll}&#10;cos(&4x&+0)&+2\\&#10;&\uparrow &\uparrow &\uparrow \\&#10;&B&C&D&#10;\end{array} &#10;\\\\\\&#10;period\qquad \cfrac{2\pi }{B}\implies \cfrac{2\pi }{4}\implies \cfrac{\pi }{2}&#10;\\\\\\&#10;\textit{horizontal/phase shift}\qquad \cfrac{C}{B}\implies \cfrac{0}{4}\implies 0\impliedby none&#10;\\\\\\&#10;\textit{vertical shift}\qquad D=+2\impliedby \textit{2 units up}

now the range, how far up and down it goes on the y-axis

well, for the graph of cos(x), the range is, goes up to 1, down to -1, is all,

the midline is at 0

now, with a vertical shift of 2 upwards, it moves the midline by 2 units, used to be at 0, now is at y = 2, but the amplitude never changed, is goes up and down still one unit,

but with the midline at 2, goes up to 3 and down to 1, so the range is 3 ⩽ y ⩽ 1
4 0
4 years ago
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