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3 years ago

Reflect the figure over the line x =

Mathematics

1 answer:

jok3333 [9.3K]3 years ago

7 0

Answer: Just re dot the points like mirror it on where ever on the graph Step-by-step explanation:

I belive that's how it's done

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how are the steps to solving an inequality similar to those for solving an equation? how are they different

juin [17]

<h2>Similarities:</h2>

With both inequalities and equations, you are solving for a variable by isolating it to one side.
A lot of properties that apply to equations apply to inequalities as well (addition property of equality, division property of equality, etc.)

<h2>Differences:</h2>

If you divide or multiply by a negative number, you must flip the inequality symbol. Dividing or multiplying by a negative number doesn't affect the equal sign.
When graphing the inequality, shaded regions (and the lines themselves if they're solid lines) are a part of the solution. When graphing an equation, only points on that line are solutions.

7 0

3 years ago

127.86<br> +78.95<br> +23.09

rjkz [21]

Answer:

229.9

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

.divide the problem.

quester [9]

Answer:

$x - 2x - 15 \: divided \: by \: x - 3$

according to the above x²-2x-15 divided by the number below x-3 first I cancel out the x
$x - 2x - 15 \: divided \: by \: - 3$
the we solve the next x-5 divided by x²-9 then as usual rule out the x
$- 5 \: divided \: by \: x - 9$
now we only have x-2x-15 divided by-3 divided by-5÷x-9 now our next step is to again single the equations out
$x - 2x - 15 \: divided \: by \: - 3 \: lets \: rue \\s \: rule \: out \: - 3 \: and \: 15 \: giving \: us \: x - 2x - 5$
now the next -5 divided by x-9 here there's nothing to rule out therefore the sign "÷" is changed to "×" cancel out the -5 and therefore we have
$x - 2x = x - 9 \: as \: final \: answer$

6 0

2 years ago

How would you describe the relationship between the real zeros and x-intercepts of the function y=log4(x-2)

notsponge [240]

Answer:

Step-by-step explanation:

First, look at y = log x. The domain is (0, infinity). The graph never touches the vertical axis, but is always to the right of it. A real zero occurs at x = 1, as log 1 = 0 => (1, 0). This point is also the x-intercept of y = log x.

Then look at y = log to the base 4 of x. The domain is (0, infinity). The graph never touches the vertical axis, but is always to the right of it. Again, a real zero occurs at x = 1, as log to the base 4 of 1 = 0 => (1, 0).

Finally, look at y=log to the base 4 of (x-2). The graph is the same as that of y = log to the base 4 of x, EXCEPT that the whole graph is translated 2 units to the right. Thus, the graph crosses the x-axis at (3, 0), which is also the x-intercept.

5 0

3 years ago

Read 2 more answers

6, -5 1/2, 0, -8/3, -0.79 from least to greatest

My name is Ann [436]

-5 1/2, -8/3, -0.79, 0, 6

6 0

3 years ago