The hashing function can take any number of key-value pairs and there is no specific limit to it.
<h3>What is hashing?</h3>
Hashing is a file-based algorithm for producing a fixed-length bit string value. A file is essentially a collection of data blocks. The length of the data is reduced by hashing to a fixed number or key that represents the original string.
When hashing is employed, the hash function may plot all of the keys and values to what the real size of the table is, demonstrating that the hashing function can take any number of key-value pairs with no restriction.
However, if the passwords are hashed in encryption, recovering the passwords is extremely difficult.
Thus, the hashing function can take any number of key-value pairs and there is no specific limit to it.
Learn more about the hashing here:
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A standard is something that is always at a certain time of the day and is scheduled the same. A protocol takes priority of anything and everything else you work on.
Answer:
int age = 10;
switch (age){
case 0:
case 1:
System.out.println("ineligible");
break;
case 2:
System.out.println("toddler");
break;
case 3:
case 4:
case 5:
System.out.println("early childhood");
break;
case 6:
case 7:
System.out.println("young reader");
break;
case 8:
case 9:
case 10:
System.out.println("elementary");
break;
case 11:
case 12:
System.out.println("middle");
break;
case 13:
System.out.println("impossible");
break;
case 14:
case 15:
case 16:
System.out.println("high school");
break;
case 17:
case 18:
System.out.println("scholar");
break;
default:
System.out.println("ineligible");
}
Explanation:
In java and many other programming languages, a switch statement is a way of having multiple branching options in a program. This is usually considered a more efficient way than using multiple if....else if statements. and the expression variables could be byte, char int primitive data types. etc. every branch (option) in a switch statement is followed by the break statement to prevent the code from "falling through". In the question The variable age is declared as an int and initialized to 10. and tested against the conditions given in the question.
Answer:
168.16.1.1 is correct.
Explanation:
168.16.1.1 is the legitimate Internet Protocol address that can be used on the Internet.
Internet Protocol 10.10.1.1 and internet Protocol 172.30.1.1 are the private internet protocol addresses so they could not be used on the internet.
The Internet Protocol 234.1.1.1 has been used as a multicast address so they may not be used on the Internet.
It would be version 14.04! I run Ubuntu Linux on my pc with dual boot with Kali Linux! I hope this helped!