DNA is copied during cell division
Answer:
Trypsin cuts at lysine and arginine amino acid residues at the carboxyl end. Chymotrypsin cuts at tryosine , phenylalanine, and tryptophan amino acid residues at the carboxyl end.
Explanation:
Trypsin and chymotrypsin are known as proteolytic enzymes which are actively involved in the digestive system. They are both secreted by the pancreas and are majorly involved in the breakdown of protein in the small intestine.
Trypsin cuts at lysine and arginine amino acid residues at the carboxyl end. Chymotrypsin cuts at tryosine , phenylalanine, and tryptophan amino acid residues at the carboxyl end.
Your answer would be Glusose
Answer:
The mentioned parental types are c+m- and c-m+. Thus, the recombinants will be c+m+ and c-m-.
Now, the given distance between c and m is 8 map units. Thus, the recombinant frequency is 8% or 0.08.
The total recombinants from 1000 plaques will come out to be 80,
Thus, the recombinants of each type will be 40.
Total parental type will be 920, and therefore, each parental type count will be 460.
Thus, expected c+m- = 460, expected c-m+ = 460, expected c+m+ = 40 and expected c-m- = 40.
