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Simora [160]
3 years ago
10

The data represents the daily rainfall​ (in inches) for one month. Construct a frequency distribution beginning with a lower cla

ss limit of and use a class width of . Does the frequency distribution appear to be roughly a normal​ distribution?
Mathematics
1 answer:
Fiesta28 [93]3 years ago
5 0

Answer:

The frequency distribution does not appear to be normal.

Step-by-step explanation:

The data provided is as follows:

S = {0.38 , 0 , 0.22 , 0.06 , 0 , 0 , 0.21 , 0 , 0.53 , 0.18 , 0 , 0 , 0.02 , 0 , 0 , 0.24 , 0 , 0 , 0.01 , 0 , 0 , 1.28 , 0.24 , 0 , 0.19 , 0.53 , 0 , 0, 0.24 , 0}

It is provided that the first lower class limit should be 0.00 and the class width should be 0.20.

The frequency distribution table is as follows:

Class Interval  Count

 0.00 - 0.19            21

 0.20 - 0.39             6

 0.40 - 0.59             2

 0.60 - 0.79             0

 0.80 - 0.99             0

  1.00 - 1 . 19             0

  1.20 - 1. 39             1

The frequency distribution does not appear to be normal. This is because the frequencies does not start and end at almost equivalent points and the mid-distribution does not consist of the highest frequency.

Thus, the frequency distribution does not appear to be normal.

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Evaluate the logarithmic equation:
evablogger [386]

Answer

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the 5 is suposed to be the subscript one.

6 0
2 years ago
What is the answer to this equation 11(-2)
kolbaska11 [484]

Answer:

The answer is -22

Step-by-step explanation:

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I am happy to assist :)

5 0
4 years ago
Read 2 more answers
14. A company uses many different delivery
ziro4ka [17]

Answer:

0.6603 = 66.03% probability that it will be sent with the ABC Speedy Delivery Company and arrive on time.

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Sent by ABC Speedy Delivery Service.

Event B: Arrived on time.

The probability that any given parcel will be sent by the ABC Speedy Delivery Service is 0.71.

This means that P(A) = 0.71

The probability that the parcel will arrive on time given the ABC Speedy Delivery Company was used is 0.93.

This means that P(B|A) = 0.93

Find the probability that it will be sent with the ABC Speedy Delivery Company and arrive on time.

This is P(A \cap B). So

P(B|A) = \frac{P(A \cap B)}{P(A)}

P(A \cap B) = P(B|A)*P(A) = 0.93*0.71 = 0.6603

0.6603 = 66.03% probability that it will be sent with the ABC Speedy Delivery Company and arrive on time.

8 0
3 years ago
How do you simplify on number 1?
Dennis_Churaev [7]
Okay. On the part that's not the whole number, see how the top number is BIGGER than the bottom? That means that it's not simplified. In order to make it simplified, you have to take a whole out of the pat that's not a whole number. Since the denominator is 12, the whole is 12/12. So, subtract it from the 13/12.

13/12-12/12=1/12

Now, since you found a whole inside of the fraction you have to add 1 to the whole number.
5+1=6

So, the answer is 6 1/12.

Thanks for the points!
6 0
3 years ago
Write an equation of a line perpendicular to the line y = -1/5x + 3 and goes through the point (-5, 6), then use Point- Slope fo
lorasvet [3.4K]
The answer is that the equation y=5x+31 is perpendicular to the equation y=-1/5x+3 and that equation passes through (-5,6) also y=5x+31 is in y=mx+b form already
y=mx+b

4 0
3 years ago
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