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Simora [160]
3 years ago
10

The data represents the daily rainfall​ (in inches) for one month. Construct a frequency distribution beginning with a lower cla

ss limit of and use a class width of . Does the frequency distribution appear to be roughly a normal​ distribution?
Mathematics
1 answer:
Fiesta28 [93]3 years ago
5 0

Answer:

The frequency distribution does not appear to be normal.

Step-by-step explanation:

The data provided is as follows:

S = {0.38 , 0 , 0.22 , 0.06 , 0 , 0 , 0.21 , 0 , 0.53 , 0.18 , 0 , 0 , 0.02 , 0 , 0 , 0.24 , 0 , 0 , 0.01 , 0 , 0 , 1.28 , 0.24 , 0 , 0.19 , 0.53 , 0 , 0, 0.24 , 0}

It is provided that the first lower class limit should be 0.00 and the class width should be 0.20.

The frequency distribution table is as follows:

Class Interval  Count

 0.00 - 0.19            21

 0.20 - 0.39             6

 0.40 - 0.59             2

 0.60 - 0.79             0

 0.80 - 0.99             0

  1.00 - 1 . 19             0

  1.20 - 1. 39             1

The frequency distribution does not appear to be normal. This is because the frequencies does not start and end at almost equivalent points and the mid-distribution does not consist of the highest frequency.

Thus, the frequency distribution does not appear to be normal.

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61 = m + - 8 what would be m
Zigmanuir [339]

Answer:

m would be 69!

Step-by-step explanation:

61 = m - 8

61 + 8 = m - 8 + 8

69 = m

7 0
3 years ago
Read 2 more answers
-21+7u=28 solve for u
ch4aika [34]

Answer:

u = 7

Step-by-step explanation:

-21 + 7u = 28

add 28 to both sides

7u = 49

divide by 7

u = 7

5 0
3 years ago
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What is the difference between 6z and z to the 6th power?
myrzilka [38]

Step-by-step explanation:

6z=z+z+z+z+z+z

z to the 6th power=z*z*z*z*z*z

7 0
3 years ago
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A firecracker shoots up from a hill 145 feet high with an initial speed of 80 feet per second. Using the formula H(t) = -16t2 +
kiruha [24]
145 = -16 t² + 80 t +s
s = ?
v = v0 - at
0 = 80 - at
80 = at
s = 80 t - at²/2
s = 80 t - 80t/2
s = 40 t
Finally: 145 = -16 t² + 80 t + 40 t
16 t² - 120 t + 145 = 0
We will solve this quadratic equation:
t = [120 +√ ( (-120)²- 4 · 16 · 145 )] / 32
t = [120 + √ (14400 - 9280) ] / 32 
t = (120 + 71.55) / 32 = 5.98 ≈ 6 s
Answer:D) 6 seconds
3 0
3 years ago
Why can the value of the variable a in the expression a + 2 be any number?
Bas_tet [7]

Answer:

(a) Because the expression is not an equation

(b) Because the expression is an equation

Step-by-step explanation:

Solving (a): a + 2

The above expression can assume any value for a because it is not an equation.

Take for instance:

a = 2;

a + 2 \to 2 + 2 = 4

a =-4

a + 2 \to -4 + 2 = -2

<em>The reason for this is because the expression is not an equation</em>

Solving (b): b + 2 = 5

The above expression can assume only value for b, and the value is:

b + 2 = 5

b = 5-2

b =3

This means that only b =3 will make the equation true.

<em>The reason for this is because the expression is an equation</em>

5 0
3 years ago
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