Answer:
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Bob = 12 x T
Sue= 8 (T +2)
12T = 8T + 16
12T-8T=8T-8T +16
4T = 16
4T/4 = 16/4
T= 4 HOURS
PLUG T BACK INTO
12(4) = 8(4) + 16
48=48
DISTANCE = 48 kilometers
Answer:
I believe it is C but then again I'm not sure good luck though
Data Set 1: (2, 2, 3, 4, 4, 5) Data Set 2: (5, 5, 10, 15, 15, 20) The difference between the interquartile ranges of the data se
vlabodo [156]
I R for data set 1 = 4-2 = 2
I R for data set2 = 15-5 = 10
Required difference is 10-2 = 8
Its 8.
JENNA
C: is my answer cuz equivakient are the same in fraction..
Step-by-step explanation:
Is this correct let me know!!
