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3 years ago

14

Two angles form a linear pair. The measure of one angle is 16∘ greater than the measure of the other angle. Find the measure of

each angle.

1 answer:

Agata [3.3K]3 years ago

4 0

A) Angle 1 + Angle 2 = 180

B) Angle 1 - Angle 2 = 16

Adding both equations:

2 * Angle 1 = 196

Angle 1 = 98

Angle 2 = 82

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This is quadratic equations <br> Help asap!!

lord [1]

Answer:

x = - 3 ± $\sqrt{2}$

Step-by-step explanation:

x² + 6x + 7 = 0 ( subtract 7 from both sides )

x² + 6x = - 7

using the method of completing the square

add ( half the coefficient of the x- term )² to both sides

x² + 2(3)x + 9 = - 7 + 9

(x + 3)² = 2 ( take square root of both sides )

x + 3 = ± $\sqrt{2}$ ( subtract 3 from both sides )

x = - 3 ± $\sqrt{2}$

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2 years ago

Solve for V:<br><br>V+9/15=0

astraxan [27]

V= 0.4

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0.6+0.4=0

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3 years ago

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vova2212 [387]

Answer:

c

Step-by-step explanation:

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2 years ago

The area of the figure. Use 3.14 for pie

balu736 [363]

Answer:

54.5 $ft^{2}$

Step-by-step explanation:

divide it to one rectangle and two different triangles.

Rectangles area: (8+3)*4 = 44 $ft^{2}$

triangle top: 4*3/2 = 6 $ft^{2}$

triangle bottom: 3*3/2= 4.5 $ft^{2}$

sum the all up: 44+6+4.5 = 54.5 $ft^{2}$

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3 years ago

An estimated 40% of all people were born after the year 2000. If two people are selected at random from around the world, what a

sukhopar [10]

The chances that NEITHER of these two selected people were born after the year 2000 is 0.36

<h3>How to determine the probability?</h3>

The given parameters are:

Year = 2000

Proportion of people born after 2000, p = 40%

Sample size = 2

The chances that NEITHER of these two selected people were born after the year 2000 is calculated as:

P = (1- p)^2

Substitute the known values in the above equation

P = (1 - 40%)^2

Evaluate the exponent

P = 0.36

Hence, the chances that NEITHER of these two selected people were born after the year 2000 is 0.36

Read more about probability at

brainly.com/question/25870256

#SPJ1

4 0

1 year ago