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3 years ago

15

A recipe calls for 1/2 cup of milk for every 3/4 cup of flour. If Kenny wants to double the recipe, how many cups of flour will

he need?

1 answer:

Marina CMI [18]3 years ago

6 0

Answer:

2\3 cups will be needed..good luck

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What are the degree and leading coefficient of the polynomial of 12u3 -8 + 23u

irga5000 [103]

Answer:

Degree: 3

Leading Coefficient: 12

Step-by-step explanation:

Find the highest power to determine the degree, in this case it's 3. Then identify the term with the highest power (12u^3) to find the leading coefficient.

So, because 3 is the largest and only power in this equation, it is the degree. 12u^3 is the leading term (term containing the highest degree) and 12 is the coefficient attatched to the term. Hope that helped!

4 0

3 years ago

PLS HELP PLS HELP PLSSSS

serious [3.7K]

Answer:

find the bottom angle of the triangle on the right side.

180 - 92 = 88

Now find x

88+36 = 124

180-124 = <u>56 = x</u>

<u />

Hope that answers your question

Don't hesitate to comment if you are confused about something

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Can anyone tell me if this is 50 or 64 please

algol [13]

I think the Answer is 64 !!!

4 0

3 years ago

What is the result of adding -3x2 - 5x + 1 and 8x2 - 2x - 9

Fudgin [204]

(-3x^2 - 5x + 1) + (8x^2 - 2x - 9)

1st remove the parenthesis

-3x^2 - 5x + 1 + 8x^2 - 2x - 9

then combine like terms

5x^2 - 7x - 8 is the final answer

6 0

3 years ago

Assuming that the equation defines x and y implicitly as differentiable functions xequalsf(t), yequalsg(t), find the slope of

Doss [256]

Answer:

$\dfrac{dx}{dt} = -8,\dfrac{dy}{dt} = 1/8\\$

Hence, the slope , $\dfrac{dy}{dx} = \dfrac{-1}{64}$

Step-by-step explanation:

We need to find the slope, i.e. $\dfrac{dy}{dx}$ .

and all the functions are in terms of $t$ .

So this looks like a job for the 'chain rule', we can write:

$\dfrac{dy}{dx} = \dfrac{dy}{dt} .\dfrac{dt}{dx} -Eq(A)$

Given the functions

$x = f(t)\\y = g(t)\\$

and

$x^3 +4t^2 = 37 -Eq(B)\\2y^3 - 2t^2 = 110 - Eq(C)$

we can differentiate them both w.r.t to $t$

first we'll derivate Eq(B) to find dx/dt

$x^3 +4t^2 = 37\\3x^2\frac{dx}{dt} + 8t = 0\\\dfrac{dx}{dt} = \dfrac{-8t}{3x^2}\\$

we can also rearrange Eq(B) to find x in terms of t , $x = (37 - 4t^2)^{1/3}$ . This is done so that $\frac{dx}{dt}$ is only in terms of t.

$\dfrac{dx}{dt} = \dfrac{-8t}{3(37 - 4t^2)^{2/3}}\\$

we can find the value of this derivative using t = 3, and plug that value in Eq(A).

$\dfrac{dx}{dt} = \dfrac{-8t}{3(37 - 4t^2)^{2/3}}\\\dfrac{dx}{dt} = \dfrac{-8(3)}{3(37 - 4(3)^2)^{2/3}}\\\dfrac{dx}{dt} = -8$

now let's differentiate Eq(C) to find dy/dt

$2y^3 - 2t^2 = 110\\6y^2\frac{dy}{dt} -4t = 0\\\dfrac{dy}{dt} = \dfrac{4t}{6y^2}$

rearrange Eq(C), to find y in terms of t, that is $y = \left(\dfrac{110 + 2t^2}{2}\right)^{1/3}$ . This is done so that we can replace y in $\frac{dy}{dt}$ to make only in terms of t

$\dfrac{dy}{dt} = \dfrac{4t}{6y^2}\\\dfrac{dy}{dt}=\dfrac{4t}{6\left(\dfrac{110 + 2t^2}{2}\right)^{2/3}}\\$

we can find the value of this derivative using t = 3, and plug that value in Eq(A).

$\dfrac{dy}{dt} = \dfrac{4(3)}{6\left(\dfrac{110 + 2(3)^2}{2}\right)^{2/3}}\\\dfrac{dy}{dt} = \dfrac{1}{8}$

Finally we can plug all of our values in Eq(A)

but remember when plugging in the values that $\frac{dy}{dt}$ is being multiplied with $\frac{dt}{dx}$ and NOT $\frac{dx}{dt}$ , so we have to use the reciprocal!

$\dfrac{dy}{dx} = \dfrac{dy}{dt} .\dfrac{dt}{dx}\\\dfrac{dy}{dx} = \dfrac{1}{8}.\dfrac{1}{-8} \\\dfrac{dy}{dx} = \dfrac{-1}{64}$

our slope is equal to $\dfrac{-1}{64}$

7 0

3 years ago