Question

Find the center and radius of this circle x^2+y^2-6x-10y+30=0

Answer 1

Answer:

Center: (3,5)

Radius: 2

Step-by-step explanation:

x² + y² - 6x - 10y + 30 = 0

Put equation into center-radius form. First regroup terms:

(x²-6x) + (y²-10y) = -30

Complete the squares:

(x²-6x+3²) + (y²-10y+5²) = -30 + 3² + 5²

(x-3)² + (y-5)² = 4 = 2²

Center: (3,5)

Radius: 2