Find the center and radius of this circle x^2+y^2-6x-10y+30=0
1 answer:
Answer:
Center: (3,5)
Radius: 2
Step-by-step explanation:
x² + y² - 6x - 10y + 30 = 0
Put equation into center-radius form. First regroup terms:
(x²-6x) + (y²-10y) = -30
Complete the squares:
(x²-6x+3²) + (y²-10y+5²) = -30 + 3² + 5²
(x-3)² + (y-5)² = 4 = 2²
Center: (3,5)
Radius: 2
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