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Ymorist [56]
2 years ago
6

My past due bill is $585, and I just made payment arrangements for the next 3 months to keep my account from being suspended. My

normal monthly bill is $50.00 per month. How much will I need to pay each month?
Mathematics
1 answer:
stiks02 [169]2 years ago
5 0
You would need to pay 245$ per month because you already own 585$. Divide 585 by 3 and get 195. then add the existing bill of 50$ and you get your answer. please mark brainliest
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Need Help ASAP!!!
Drupady [299]

Answer:

B) {(-2, -3), (-3, -2), (2, 3), (3, 2)}

Step-by-step explanation:

A function cannot have replicated x-coordinates. All the other answer choices do, so you would pick this one.

I am joyous to assist you anytime.

8 0
3 years ago
Application 11. Dasha took out a loan of $500 in oeder to buy the # 1 selling book in the world, "Math, What is it Good For?" by
finlep [7]

Answer:

\boxed{\text{\$581.25; \$81.25}}

Step-by-step explanation:

The formula for the total accrued amount is

A = P(1 + rt)

Data:

P = $500

r = 6.5 % = 0.065

t = 30 mo

Calculations:

(a) Convert months to years

t = 30 mo × (1 yr/12 mo) = 2.5 yr

(b) Calculate the accrued amount

A = 500(1 + 0.065 × 2.5)

  = 500(1 + 0.1625)

  = 500 × 1.1625

  = 581.25

\text{Dasha will have to pay back }\boxed{\textbf{\$581.25}}

(c) Calculate the accumulated interest

\begin{array}{rcl}A & = & P + I\\581.25 & = & 500 + I\\I & = & 81.25\\\end{array}\\\text{The accumulated interest is }\boxed{\textbf{\$81.25}}

6 0
2 years ago
Sally lives in City A and works for the department of transportation. She needs to inspect the weigh stations in each of four di
galben [10]

Answer:

She can visit the cities in 192 ways

Step-by-step explanation:

If Sally starts from city A and after going to 4 cities she returns to home,

then that can be in 4! = 24 ways. (permutation of 4 distinct objects)

If between the time she visits cities, she comes home once,

then cities can be visited in,

4! \times 3_{C_{1}} = 72 ways.  (permutation of 4      distinct objects  and choosing 1 gap among the 3 )

If between the time she visits cities, she comes home twice,

then cities can be visited in,

4! \times 3_{C_{2}} =72 ways. (permutation of 4 distinct objects and finding 2 gaps among the 3)

If between the time she visits cities, she comes home thrice,

then cities can be visited in,

4! \times 3_{C_{3}} = 24 ways. (permutation of 4 distinct objects and choosing 3 gaps among the 3)

Now, she can't come home more than thrice in between the time she visits cities (since there are 4 cities to visit only)

So, the number of ways she can visit cities = (24+ 72 + 72 + 24)

                                                                       = 192

6 0
3 years ago
Plz give answer fast.
maks197457 [2]

Answer:

plz mark brainliest✌️✌️

3 0
3 years ago
Select the correct answer from the drop-down menu. The lengths of three line segments are 4 centimeters, 5 centimeters, and 9 ce
MrMuchimi
I believe the answer is (B) 1 TIME
4 0
3 years ago
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