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1 year ago

Question 4 of 10

Mathematics

2 answers:

Artist 52 [7]1 year ago

7 0

The answer is D to the next step

LuckyWell [14K]1 year ago

5 0

The answer is D because it makes the most sense :)

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Is 6^-2 positive or negative? Explain.

Gnoma [55]

Answer:

It's positive when you have 6^-2 it's the same as having $(\frac{1}{6})^{2} \\$ . So 6^-2 it's 1/36.

Step-by-step explanation:

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3 years ago

PLZ HELP AND IF U TAKE MY POINTS I WILL REPORT U AN WHO EVER HELPS I WIL GIVE BRAINIEST

Sphinxa [80]

Answer:

the second one I can't give a explanation cause my wrist is broken so it's harder to type hope this helps

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2 years ago

Lamar sells another broker's $800,000 listing for $785,000 at a commission rate of 6.5%. Lamar has a 40% commission split with h

Serggg [28]

Total commission that Lamar got is:
6.5/100×785,000
=$51,025
Amount that Lamar split with his broker:
40/100×51025
=$20410
Amount that brokerage split
=50/100×20410
$10205

Total amount Lamar received $10205

4 0

2 years ago

Read 2 more answers

If the mean weight of 4 backfield members on the football team is 221 lb and the mean weight of the 7 other players is 202 lb, w

MatroZZZ [7]

Let $x_1, x_2, x_3, x_4, x_5, x_6, x_7, x_8, x_9, x_{10}, x_{11}$ be the weight of i-th player.

1. If the mean weight of 4 backfield members on the football team is 221 lb, then

$\dfrac{x_1+x_2+x_3+x_4}{4}=221\ lb.$

2. If the mean weight of the 7 other players is 202 lb, then

$\dfrac{x_5+x_6+x_7+x_8+x_9+x_{10}+x_{11}}{7}=202\ lb.$

3. From the previous statements you have that

$x_1+x_2+x_3+x_4=221\cdot 4=884 \lb,\\ \\x_5+x_6+x_7+x_8+x_9+x_{10}+x_{11}=202\cdot 7=1414\ lb.$

Add these two equalities and then divide by 11:

$x_1+x_2+x_3+x_4+x_5+x_6+x_7+x_8+x_9+x_{10}+x_{11}=884+1414=2298\ lb,\\ \\\dfrac{x_1+x_2+x_3+x_4+x_5+x_6+x_7+x_8+x_9+x_{10}+x_{11}}{11}=\dfrac{2298}{11}=208\dfrac{10}{11}\ lb.$

Answer: the mean weight of the 11-person team is $208\dfrac{10}{11}\ lb.$

4 0

2 years ago

Help me this assignment is due soon.

AlekseyPX

So maybe it’s 5, it’s equivalent to the side with 6, just shorter

6 0

2 years ago