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snow_tiger [21]
3 years ago
10

What is 100kg decrease by 12.5%

Mathematics
2 answers:
kherson [118]3 years ago
8 0

Turn the percentage into decimal: 12.5 / 100 = 0.125

Multiply: 100 * 0.125 = 12.5

Subtract: 100 - 12.5 = 87.5

~Good luck

erma4kov [3.2K]3 years ago
3 0

Answer:

87.5

Step-by-step explanation:

100 - (12.5% × 100)

100 - 12.5% × 100

(1 - 12.5%) × 100

(100% - 12.5%) × 100

87.5% × 100

87.5 ÷ 100 × 100

87.5 × 100 ÷ 100

8,750 ÷ 100 = 87.5

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Alex73 [517]

Answer:

1. -15

2. 35

3. -60

4. 5

Step-by-step explanation:

n = 16:

-5/6(2+16)

-5/6(18)

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n= -44:

-5/6(2-44)

-5/6(-42)

35

n = 70:

-5/6(2+70)

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7 0
2 years ago
-36 ÷ 4 A) 4 groups of 9 negatives B) 4 groups of 9 positives C) 9 groups of 4 negatives D) 9 groups of 4 positives
Valentin [98]

Answer:

A) 4 groups of 9 negatives

Step-by-step explanation:

-36/4

-9

This means we have 4 groups of 9 negatives

7 0
3 years ago
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PLEASE HELP!!!!!!!dgbdgdbhdndcn
bogdanovich [222]
Problem 1)

AC is only perpendicular to EF if angle ADE is 90 degrees

(angle ADE) + (angle DAE) + (angle AED) = 180
(angle ADE) + (44) + (48) = 180
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(angle ADE) + 92 - 92 = 180 - 92
angle ADE  = 88

Since angle ADE is actually 88 degrees, we do NOT have a right angle so we do NOT have a right triangle

Triangle AED is acute (all 3 angles are less than 90 degrees)

So because angle ADE is NOT 90 degrees, this means AC is NOT perpendicular to EF

-------------------------------------------------------------

Problem 2)

a) The center is (2,-3) 

The center is (h,k) and we can see that h = 2 and k = -3. It might help to write (x-2)^2+(y+3)^2 = 9 into (x-2)^2+(y-(-3))^2 = 3^3 then compare it to (x-h)^2 + (y-k)^2 = r^2

---------------------

b) The radius is 3 and the diameter is 6

From part a), we have (x-2)^2+(y-(-3))^2 = 3^3 matching (x-h)^2 + (y-k)^2 = r^2

where
h = 2
k = -3
r = 3

so, radius = r = 3
diameter = d = 2*r = 2*3 = 6

---------------------

c) The graph is shown in the image attachment. It is a circle with center point C = (2,-3) and radius r = 3.

Some points on the circle are

A = (2, 0)
B = (5, -3)
D = (2, -6)
E = (-1, -3)

Note how the distance from the center C to some point on the circle, say point B, is 3 units. In other words segment BC = 3.

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