Answer:
0.6672 is the required probability.
Step-by-step explanation:
We are given the following information in the question:
Mean, μ = 8.4 minutes
Standard Deviation, σ = 3.5 minutes
We are given that the distribution of distribution of taxi and takeoff times is a bell shaped distribution that is a normal distribution.
According to central limit theorem the sum measurement of n is normal with mean 
and standard deviation 
Sample size, n = 37
Standard Deviation =
P(taxi and takeoff time will be less than 320 minutes)
Calculation the value from standard normal z table, we have,
0.6672 is the probability that for 37 jets on a given runway, total taxi and takeoff time will be less than 320 minutes.
y2-y1 / x2-x1 is how to get slop3 for 2 points (x1,y1) and (x2, y2). So 4-1 / 2-0 and the slope is 3/2. If this is right could you possibly give me brainliest? Hope this helped.
Answer:
Step-by-step explanation:
Given that that (X) the amount of time lapsed between consecutive trades on the New York Stock Exchange followed a normal distribution with a mean of 15 seconds.
i.e. X is normal with mean = 15 and unknown std deviation 
Given that
i.e. P(
z=-1.475 (from normal table)
Hence 
Using this we find P(X>17) = 
Given:
μ = 2 min, population mean
σ = 0.5 min, population standard deviation
We want to find P(x>3).
Calculate the z-score
z= (x-μ)/σ = (3-2)/0.5 = 2
From standard tables, obtain
P(x ≤ 3) = P(z ≤ 2) = 0.9772
Therefore
P(x > 3) = P(z > 2) = 1 - 0.9772 = 0.0228
Answer: 0.02275
The car traveled 23600 meters
