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finlep [7]
3 years ago
11

5. An attacker swings a board with a mass of 2 kg toward a victim. The acceleration is 10 m/s2 when the board hits the victim. H

ow much force did the board exert on the victim? Obj. 7.2​
Mathematics
1 answer:
suter [353]3 years ago
6 0

The force exerted on victim is 20 newton

<em><u>Solution:</u></em>

An attacker swings a board with a mass of 2 kg toward a victim

The acceleration is 10 m/s^2 when the board hits the victim

To find: Force exerted on victim

<em><u>The force is given by formula:</u></em>

F = mass \times acceleration

From given,

mass = 2 \text{ kg }\\\\Acceleration = 10 m/s^2

<em><u>Substituting the values in formula,</u></em>

Force = 2 \times 10 = 20

Thus force exerted on victim is 20 newton

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The answer is:  " 471 cm² " .
_____________________________________________________
The formula for the surface area, "S.A.", of a "cylinder":

S.A. =  2 π r² + 2 π r h ; 

in which:

"S.A." = "surface area" of the cylinder; for which we wish to solve; 

 π = 3.14 (approximation we shall use) ;

  r = radius = 5 cm (given; from figure); 

  h = height = 2 cm (given; from figure);
______________________________________
To solve for the surface area, "S.A." . let us plug in our known values, and solve:


S.A. =  2 π r²   +    2 π r h  ; 


S.A. = 2 * (3.14) * (5 cm)²  +  2 * (3.14) * (5 cm) * 10 cm)  ;

        = 2 * (3.14) * (5²) * (cm²)   +    2 * (3.14) * 5* 10 * cm² ;

        = 2 * (3.14) * (25) * (cm²)  +    2 * (3.14) * 5* 10 * cm²  ;

        = 157 cm²  +  314 cm²  ;

        =  471 cm² .
________________________________________________
The answer is:  " 471 cm² " .
________________________________________________
4 0
4 years ago
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