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finlep [7]
2 years ago
11

5. An attacker swings a board with a mass of 2 kg toward a victim. The acceleration is 10 m/s2 when the board hits the victim. H

ow much force did the board exert on the victim? Obj. 7.2​
Mathematics
1 answer:
suter [353]2 years ago
6 0

The force exerted on victim is 20 newton

<em><u>Solution:</u></em>

An attacker swings a board with a mass of 2 kg toward a victim

The acceleration is 10 m/s^2 when the board hits the victim

To find: Force exerted on victim

<em><u>The force is given by formula:</u></em>

F = mass \times acceleration

From given,

mass = 2 \text{ kg }\\\\Acceleration = 10 m/s^2

<em><u>Substituting the values in formula,</u></em>

Force = 2 \times 10 = 20

Thus force exerted on victim is 20 newton

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erastovalidia [21]

Answer:

100.5cm2

Step-by-step explanation:

v=pi(r)2(h)

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v=3.14(4)(8)

v=100.48

v=100.5cm2

7 0
3 years ago
5. If the dimensions of a rectangle are doubled, which of the following best describes an effect on the rectangle?​
Bond [772]

Answer:

Since length and width are perpendicular, Doubling either one will double the area. So Doubling both will quadruple the area. 2x2 = 4.

This idea works if the dimensions doubled are those that are used to compute area. Like the base and height of a triangle.

More generally, in a polygon, if all the sides are doubled, the area is multiplied by 4. In a circle, Doubling the radius will quadruple the area.

In 3 dimensions, Doubling one dimension will double the VOLUME. Doubling two perpendicular dimensions will quadruple the volume and Doubling 3 perpendicular dimensions will multiply the volume by 2x2x2 or 8.

Step-by-step explanation:

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7 0
2 years ago
Solve the system of equations 5x+9y+9z=5 4x+9y+6z=10 2x+2y+5z=9
erma4kov [3.2K]

Answer:

{x,y,z} = {-116,28,37}

Step-by-step explanation:

// Solve equation [3] for the variable  z  

 

 [3]    5z = -2x - 2y + 9

 [3]    z = -2x/5 - 2y/5 + 9/5

__________________________________________________________

// Plug this in for variable  z  in equation [1]

  [1]    5x + 9y + 9•(-2x/5-2y/5+9/5) = 5

  [1]    7x/5 + 27y/5 = -56/5

  [1]    7x + 27y = -56

__________________________________________________________

// Plug this in for variable  z  in equation [2]

  [2]    4x + 9y + 6•(-2x/5-2y/5+9/5) = 10

  [2]    8x/5 + 33y/5 = -4/5

  [2]    8x + 33y = -4

__________________________________________________________

// Solve equation [2] for the variable  y  

 

 [2]    33y = -8x - 4

 [2]    y = -8x/33 - 4/33

__________________________________________________________

// Plug this in for variable  y  in equation [1]

  [1]    7x + 27•(-8x/33-4/33) = -56

  [1]    5x/11 = -580/11

  [1]    5x = -580

__________________________________________________________

// Solve equation [1] for the variable  x  

  [1]    5x = - 580  

  [1]    x = - 116

__________________________________________________________

// By now we know this much :

   x = -116

   y = -8x/33-4/33

   z = -2x/5-2y/5+9/5

__________________________________________________________

// Use the  x  value to solve for  y  

   y = -(8/33)(-116)-4/33 = 28

__________________________________________________________  

// Use the  x  and  y  values to solve for  z  

 z = -(2/5)(-116)-(2/5)(28)+9/5 = 37

╦────────────────────────────╦

│Hope this helped  _____________________│    

│~Derelis ____________________________ │

╨___________________________________╨                  

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Answer:

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Step-by-step explanation:

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Answer:

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