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3 years ago

Please help faaaaast!!!! First answer gets brainliest!!!!!!!

Mathematics

1 answer:

wlad13 [49]3 years ago

3 0

Answer:

i think its C but i could be wrong

Step-by-step explanation:

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PLEASE HELP Christine walks 0.5 miles around the lake in 10 minutes.

grin007 [14]

Answer:

Her speed is 0.05 miles per minute

Step-by-step explanation:

The unit rate of her speed in miles per minute is given by the number of miles divided by the number of minutes. So:

0.5 miles in 10 minutes. So

0.5/10 = 0.05 miles per minute

Her speed is 0.05 miles per minute

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2 years ago

The incenter of a triangle is the intersection point of the_____ bisectors

adelina 88 [10]

Answer:

angle

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Which of the following expressions is equal to 5^6/5^2? A) 5 • 5 • 5 • 5 B) 5 • 5 • 5 C) 1/5•5•5•5 D) 3

lana66690 [7]

Step-by-step explanation: To simplify, we will apply the <em>Quotient Rule</em>.

The 5's in this problem are bases so as you apply the quotient rule,

subtract the exponents but leave the base alone to get 5⁴.

We can also write 5⁴ as 5 · 5 · 5 · 5.

6 0

3 years ago

PLEASE HELP FAST!!

Oduvanchick [21]

Answer:

x = 4

Step-by-step explanation:

10 = -1/4 x + 11

10 - 11 = -1/4 x

-1 = - 1/4 x

x = 4

7 0

3 years ago

Suppose X has an exponential distribution with mean equal to 23. Determine the following:

e-lub [12.9K]

Answer:

a) P(X > 10) = 0.6473

b) P(X > 20) = 0.4190

c) P(X < 30) = 0.7288

d) x = 68.87

Step-by-step explanation:

Exponential distribution:

The exponential probability distribution, with mean m, is described by the following equation:

$f(x) = \mu e^{-\mu x}$

In which $\mu = \frac{1}{m}$ is the decay parameter.

The probability that x is lower or equal to a is given by:

$P(X \leq x) = \int\limits^a_0 {f(x)} \, dx$

Which has the following solution:

$P(X \leq x) = 1 - e^{-\mu x}$

The probability of finding a value higher than x is:

$P(X > x) = 1 - P(X \leq x) = 1 - (1 - e^{-\mu x}) = e^{-\mu x}$

Mean equal to 23.

This means that $m = 23, \mu = \frac{1}{23} = 0.0435$

(a) P(X >10)

$P(X > 10) = e^{-0.0435*10} = 0.6473$

P(X > 10) = 0.6473

(b) P(X >20)

$P(X > 20) = e^{-0.0435*20} = 0.4190$

P(X > 20) = 0.4190

(c) P(X <30)

$P(X \leq 30) = 1 - e^{-0.0435*30} = 0.7288$

P(X < 30) = 0.7288

(d) Find the value of x such that P(X > x) = 0.05

$P(X > x) = e^{-\mu x}$

$0.05 = e^{-0.0435x}$

$\ln{e^{-0.0435x}} = \ln{0.05}$

$-0.0435x = \ln{0.05}$

$x = -\frac{\ln{0.05}}{0.0435}$

$x = 68.87$

5 0

3 years ago