HERES THE ANSWER AND EXPLINATION
⇒Associative property of Addition is applied for three real numbers.For, any three real numbers, A, B and C
≡A+B+C=A+(B+C)=(A+B)+C=(A+C)+B→→→Associative Property of Addition
that is , we can add any two numbers first and then the third number with them.
⇒Also, Commutative Property of Addition of two numbers says that for any two numbers , A and B
≡A+B=B+A
We have to find equivalent expression using Associative Property of the sum of set of three numbers
→→(13+15+20)+(20+47+18)
Answer Written by Jerry
→(20+13+15)+(20+47+18)
Answer Written by Layla
→(20+47+18)+(13+15+20)
The Expression Written by Keith and Melinda is Incorrect,because they haven't used the bracket Properly, as associative property says that you can add any two numbers first and then the third number among three numbers.
→→Number of Students who has applied the Associative property Correctly
Option B ⇒Two(Jerry, Layla)
Provide the measurements of the court in the book, please.
Answer: 0.31 or 31%
Let A be the event that the disease is present in a particular person
Let B be the event that a person tests positive for the disease
The problem asks to find P(A|B), where
P(A|B) = P(B|A)*P(A) / P(B) = (P(B|A)*P(A)) / (P(B|A)*P(A) + P(B|~A)*P(~A))
In other words, the problem asks for the probability that a positive test result will be a true positive.
P(B|A) = 1-0.02 = 0.98 (person tests positive given that they have the disease)
P(A) = 0.009 (probability the disease is present in any particular person)
P(B|~A) = 0.02 (probability a person tests positive given they do not have the disease)
P(~A) = 1-0.009 = 0.991 (probability a particular person does not have the disease)
P(A|B) = (0.98*0.009) / (0.98*0.009 + 0.02*0.991)
= 0.00882 / 0.02864 = 0.30796
*round however you need to but i am leaving it at 0.31 or 31%*
If you found this helpful please mark brainliest
Answer:
$30
Step-by-step explanation:
$160-$130=$30
