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Aleks [24]
4 years ago
12

How do I solve (3+i)(3-i)

Mathematics
2 answers:
diamong [38]4 years ago
7 0
(3+i)(3-i)=3(3-i)+i(3-i)=9-3i+3i-i^2=9-(-1)=\\\\=9+1=10
nalin [4]4 years ago
3 0
(3+I)(3-1)
-i^2+9=0
-I^2=-9
I^2=9
i= + or - 3
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