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3 years ago

Enter you answer and show all the steps that you use to solve this problem in the space provided.

Mathematics

1 answer:

Goshia [24]3 years ago

5 0

Answer:

Y=38

X=142

Z=142

Step-by-step explanation:

Not sure about z but I know Y and X are right I hope sorry

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Triangle DEF is shown. If a circle is inscribed in the triangle, which angle bisectors will pass through the center of the circl

Goshia [24]

<span>B) the bisectors of angles D, E, and F
</span>
In an inscribed circle of a triangle, all angle bisectors will pass through the center of the circle.

Pls. see attachment.

1st attachment is Triangle DEF. 2nd attachment is how inscribed circle relates to the triangle it is inscribed in.

4 0

3 years ago

Read 2 more answers

Can somebody help me please.

Svetradugi [14.3K]

The sum is -3.3z - 11

3 0

3 years ago

The volume of a cubic cardboard box is 125/8 ft3.

lina2011 [118]

Answer:

The answer is

Step-by-step explanation:

Since the cardboard box is a cube all it's sides are equal

Volume(V) of a cube = l³

where l is the length of one side

From the question

$V = \frac{125}{8} \: {ft}^{3}$

The length of each side of the cardboard box is

${l}^{3} = \frac{125}{8} \\ \sqrt[3]{ {l}^{3} } = \sqrt[3]{ \frac{125}{8} } \\ l = \frac{5}{2}$

We have the final answer as

$\frac{5}{2} \: \: \: feet \\$

Hope this helps you

5 0

3 years ago

If (sin(()−1))p =2cos(()−1)q , show that p^2 =4q^2 (1− q^2) ?.

Papessa [141]

Likely the equation is

$\sin^{-1}p=2\cos^{-1}q$

For either side to be defined, we require $|p|\le1$ and $|q|\le1$ . Under these conditions, we can take

$\sin(\sin^{1}p)=\sin(2\cos^{-1}q)$
$\implies p=2\sin(\cos^{-1}q)\cos(\cos^{-1}q)$
$\implies p=2q\sin(\cos^{-1}q)$
$\implies p=2q\sqrt{1-q^2}$
$\implies p^2=4q^2(1-q^2)$

as required.

8 0

4 years ago

Equation of a line perpendicular to y=-11x-4 going through (3,3)

lutik1710 [3]

Answer: y = $\frac{x}{11}$ + 30/11

Step-by-step explanation:

Two line are said to be perpendicular to each other if the slope of the first line = -1 / the slope of the second line , that is

If the slope of the first line is M1 and the slope of the second line is M2 , then M1 = -1 / M2.

From the equation given , M1 = - 11 , that means M2 = 1 / 11

Using the formula y - y1 = m ( x - x1) to calculate the equation , we have

y - 3 = 1/11 ( x - 3)

Multiply through by 11 , we have

11 ( y - 3 ) = x - 3

11y - 33 = x - 3

11y = x + 30

y = x/11 + 30/11

5 0

3 years ago