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s2008m [1.1K]
3 years ago
9

How do calculate surface area of a square

Mathematics
2 answers:
svet-max [94.6K]3 years ago
5 0
The surface area would be 50
Lina20 [59]3 years ago
3 0
The surface area of a square is determined by multiplying the length and width by each other, for example:

If a square is 10 units high and 5 units long, then the surface area would be 50 units.
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Cscθ - sinθ = _____
galina1969 [7]
So you maybe know that \csc x = \frac{1}{\sin x}. Now let us try to simplify the expression

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4 years ago
The number of dogs in a pet store decreased from 35 to 31.
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The answer is A. 11% when it it rounded to the nearest percent
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Consider the following function. f(x) = 16 − x2/3 Find f(−64) and f(64). f(−64) = f(64) = Find all values c in (−64, 64) such th
VARVARA [1.3K]

Answer:

This does not contradict Rolle's Theorem, since f '(0) = 0, and 0 is in the interval (−64, 64).

Step-by-step explanation:

The given function is

f(x)=16-\frac{x^2}{3}

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f(-64)=16-\frac{(-64)^2}{3}

f(-64)=16-\frac{4096}{3}

f(-64)=-\frac{4048}{3}

To find f(64), we substitute x=64 into the function.

f(64)=16-\frac{(64)^2}{3}

f(64)=16-\frac{4096}{3}

f(64)=-\frac{4048}{3}

To find f'(c), we must first find f'(x).

f'(x)=-\frac{2x}{3}

This implies that;

f'(c)=-\frac{2c}{3}

f'(c)=0

\Rightarrow -\frac{2c}{3}=0

\Rightarrow -\frac{2c}{3}\times -\frac{3}{2}=0\times -\frac{3}{2}

c=0

For this function to satisfy the Rolle's Theorem;

It must be continuous on [-64,64].

It must be differentiable  on (-64,64).

and

f(-64)=f(64).

All the hypotheses are met, hence this does not contradict Rolle's Theorem, since f '(0) = 0, and 0 is in the interval (−64, 64) is the correct choice.

6 0
3 years ago
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Vinil7 [7]

Answer:  

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Step-by-step explanation:

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Natali [406]

Answer:

100/100'000*5 = 5000 + base commission of 100'000 = 105'000

Step-by-step explanation:

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3 years ago
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