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4 years ago

#16 please help me solve this

Mathematics

2 answers:

const2013 [10]4 years ago

7 0

Answer:

x=-5, y=4

Step-by-step explanation:

4x - 3y = -32

x = 2y -13

Use the second equation to substitute for x in the first equation

4(2y-13) -3y = -32

Distribute

8y -52-3y = -32

Combine like terms

5y -52 = -32

Add 52 to each side

5y -52+52 = -32+52

5y = 20

Divide by 5

5y/5 = 20/5

y=4

Now we need to solve for x

x = 2y-13

=2(4) -13

8-13

= -5

Ivahew [28]4 years ago

6 0

Answer:

y=4, x=-5

Step-by-step explanation:

Ⓗⓘ ⓣⓗⓔⓡⓔ

Well, we could merge the two equations together to do as shows:

4(2y-13)-3y=-32

8y-52-3y=-32

5y-52=-32

5y=20

y=4

To find x, we'd do

4x-3(4)=-32

4x-12=-32

4x=-20

x=-5

(っ◔◡◔)っ ♥ Hope this helped, have a great day! ♥

˜”*°•.˜”*°• ~Star •°*”˜.•°*”˜

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Answer: The correct answer is:

______________

→ Choice: [C]: " $\frac{2}{1} * \frac{7}{-2}$ " .

______________

Step-by-step explanation:

______________

Note that this problem contains multiplication and division.

WIth multiplication and division;

the order of operations we perform is from "left side to right side" in the expression; in the order in which the operation occurs:

As such:

______________

The given problem:

______________

" $\frac{-3}{4} * \frac{7}{-2}$ ÷ $\frac{3}{-8}$ " ;

Is treated as:

______________

" $(\frac{-3}{4} * \frac{7}{-2})$ ÷ $\frac{3}{-8}$ " ;

______________

So, we start with:

______________

" $\frac{-3}{4} * \frac{7}{-2}$ " ;

______________

→ $\frac{-3}{4} * \frac{7}{-2} = \frac{(-3*7)}{[4*(-2) ]} = \frac{-21}{-8}$ ;

______________

Simplify:

______________

" $\frac{-21}{-8} = \frac{(-1)*21}{(-1) *8}$ " ;

______________

→ The "(-1)'s " cancel out:

{since: "(-1)/(-1) = 1 "} ;

→ And we have: " $\frac{21}{8}$ " ;

______________

Now, continue with the problem, and divide this value by: " $\frac{3}{-8}$ " ;

______________

" $\frac{21}{8}$ ÷ $\frac{3}{-8}$ " ;

______________

Note that dividing by a number is the same as multiplying by the reciprocal of that said number:

______________

The reciprocal of " $\frac{3}{-8}$ " ; is: " $\frac{-8}{3}$ : l

As such:

" $\frac{21}{8}$ ÷ $\frac{3}{-8}$ " ;

______________

= " $\frac{21}{8} * \frac{-8}{3}$ "

______________

Now, let us simplify:

Note: The "8" and the "-8" ;

The "8" can be changed to "1" ; and the "-8" can be changed to "-1" ;

since: "-8 ÷ 8 = 1 " ; and since: "8 ÷ 8 = 1 " ;

Note: The "3" and the "21" ;

The "3" can be changed to "1"; and the "21" can be changed to "7" ;

since: "21 ÷ 3 = 7 " ; and since: "3 ÷ 3 = 1 " ;

______________

And we can we rewrite the expression:

______________

→ " $\frac{7}{1} * \frac{-1}{1}$ " ;

which equals: " 7 * -1 " ; which equals " - 7 ".

______________

Now, the problem has 4 (four) answer choices. Which expression [i.e. which answer choice] is equal to: " -7 " ??

______________

Consider Choice [A]: " $\frac{1}{2} * \frac{7}{2}$ " ; which equals: " $\frac{(1*7)}{(2*2)} = \frac{7}{4} = 1\frac{3}{4}$ " ;

" $1\frac{3}{4} \neq -7$ ."

Rule out: "Choice [A]."

______________

Consider Choice: [B]: " $\frac{2}{1} * \frac{7}{2}$ " ; which equals: " $\frac{(2*7)}{(1*2)} = \frac{14}{2} = 7$ ; " $7\neq -7$ ."

Rule out: "Choice: [B]."

______________

Consider Choice: [C]: " $\frac{2}{1} * \frac{7}{-2}$ " ; which equals: " $-7$ ; " $-7 = -7$ ".

Choice [C]: seems correct!

______________

Consider Choice: [D]: " $\frac{-1}{2} * \frac{7}{-2}$ " ; which equals:

" $\frac{(-1*7)}{(2*-2)} = \frac{-7}{-4} = \frac{(-1)*7}{(-1)*4}$ ;

→ cancel out the "(-1)'s" ;

→ {since: "(-1) / (-1) = 1 " ;

to get:

→ " $\frac{7}{4}$ " ; which equals:

→ " $1\frac{3}{4}$ " ; " $1\frac{3}{4} \neq -7$ . "

Rule out: "Choice: [D]."

______________

The correct answer is:

______________

Choice: [C]: " $\frac{2}{1} * \frac{7}{-2}$ " .

______________

Hope this is helpful to you!

Wishing you the best!

______________

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