Graph the line that has a slope of -1.2 and passes through (-7, 4). Use graph paper.
1 answer:
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We have to prove that rectangles are parallelograms with congruent Diagonals.
Solution:
1. ∠R=∠E=∠C=∠T=90°
2. ER= CT, EC ║RT
3. Diagonals E T and C R are drawn.
4. Shows Quadrilateral R E CT is a Rectangle.→→[Because if in a Quadrilateral One pair of Opposite sides are equal and parallel and each of the interior angle is right angle than it is a Rectangle.]
5. Quadrilateral RECT is a Parallelogram.→→[If in a Quadrilateral one pair of opposite sides are equal and parallel then it is a Parallelogram]
6. In Δ ERT and Δ CTR
(a) ER= CT→→[Opposite sides of parallelogram]
(b) ∠R + ∠T= 90° + 90°=180°→→→Because RECT is a rectangle, so ∠R=∠T=90°]
(c) Side TR is Common.
So, Δ ERT ≅ Δ CTR→→[SAS]
Diagonal ET= Diagonal CR →→→[CPCTC]
In step 6, while proving Δ E RT ≅ Δ CTR, we have used
(b) ∠R + ∠T= 90° + 90°=180°→→→Because RECT is a rectangle, so ∠R=∠T=90°]
Here we have used ,Option (D) : Same-Side Interior Angles Theorem, which states that Sum of interior angles on same side of Transversal is supplementary.
<span>the y-intercept will be 
</span>the standard line equation is y = mx + b, where y is the y point, x is the x point, m is the slope, and b is the y-intercept.
to get the y intercept, we need to transform into the line equation, and caculate out b.
3x + 5y = 8
so 5y = 8 -3x
then y = <span> - <span>
x
which means that <span> = the y intercept.</span></span></span>
</span>the standard line equation is y = mx + b, where y is the y point, x is the x point, m is the slope, and b is the y-intercept.
to get the y intercept, we need to transform into the line equation, and caculate out b.
3x + 5y = 8
so 5y = 8 -3x
then y = <span>
which means that <span>