A coin is tossed 3 times. Find the probability of getting at least one tail
2 answers:
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In order for the mode to be 6, there must be more of them than any other number. In order for the mean to be 3.5, most of the distribution must lie at 3 or below to balance the large number of 6s. For the median to be 3, there must be as many scores at or above 3 as at or below 3. Thus, we choose to have most of the distribution with values 1, 2, 3 and only enough 6s to make that be the mode.
Answer:
Step-by-step explanation:
We are given that
We have to find the angle BDC.
In triangle ABC
Sum of interior angles of triangle=180 degrees
Angles subtended on the same are ac are equal.
Answer:
Since P(male)xP(fail) = 0.0549 and and P(male and fail) = 0.0773, the two results are different, so the events are not independent.
Step-by-step explanation:
Independent events:
Two events, A and B are independent, if:
Probability of male:
58 + 14 = 72 males out of 58 + 14 + 98 + 11 = 181
So
P(male) = 72/181 = 0.3978
Probability of failling:
14 + 11 = 25 students fail out of 181. So
P(fail) = 28/181 = 0.1381
Multiplitication of male and failling:
0.3978*0.1381 = 0.0549
Probability of being male and failing:
14 out of 181. So
14/181 = 0.0773
Different probabilities, so not independent.
Since P(male)xP(fail) = 0.0549 and and P(male and fail) = 0.0773, the two results are different, so the events are not independent.