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Nataly_w [17]
3 years ago
12

A group of students at a high school took a standardized test. The number of students who passed or failed the exam is broken do

wn by gender in the following table. Determine whether gender and passing the test are independent by filling out the blanks in the sentence below, rounding all probabilities to the nearest thousandth.
Passed Failed
Male 58 14
Female 98 11
Since P(male)xP(fail) = ___and P(male and fail)= ,___ the two results are_______ - so the events are________
Mathematics
1 answer:
Anuta_ua [19.1K]3 years ago
5 0

Answer:

Since P(male)xP(fail) = 0.0549 and and P(male and fail) = 0.0773, the two results are different, so the events are not independent.

Step-by-step explanation:

Independent events:

Two events, A and B are independent, if:

P(A \cap B) = P(A)P(B)

Probability of male:

58 + 14 = 72 males out of 58 + 14 + 98 + 11 = 181

So

P(male) = 72/181 = 0.3978

Probability of failling:

14 + 11 = 25 students fail out of 181. So

P(fail) = 28/181 = 0.1381

Multiplitication of male and failling:

0.3978*0.1381 = 0.0549

Probability of being male and failing:

14 out of 181. So

14/181 = 0.0773

Different probabilities, so not independent.

Since P(male)xP(fail) = 0.0549 and and P(male and fail) = 0.0773, the two results are different, so the events are not independent.

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What is the correct answer?
Tasya [4]

Given:

The function is

f(x)=(x+3)^2(x-5)^6

To find:

The zeros of the given function.

Solution:

The general form of polynomial is

P(x)=a(x-c_1)^{m_1}(x-c_2)^{m_2}...(x-c_n)^{m_n}       ...(i)

where, a is a constant, c_1,c_2,...,c_n are zeros of respective multiplicities m_1,m_2,...,m_n.

We have,

f(x)=(x+3)^2(x-5)^6

On comparing this with (i), we get

c_1=-3,m_1=2

c_2=5,m_2=6

It means, -3 is a zero with multiplicity 2 and 5 is a zero with multiplicity 6.

Therefore, the correct option is B.

5 0
2 years ago
HELP!
Klio2033 [76]
It’s 50/50 hope this helps
4 0
3 years ago
Read 2 more answers
Directions: Complete all 3 questions. Make sure you include a graph, work and conclusion.
Simora [160]

Prove that the quadrilateral whose vertices are I(-2,3), J(2,6), K(7,6), and L(3, 3) is a rhombus.

I think in these problems the first step is to express each side as a vector.  A vector is the difference between points.  When two sides have the same vector (or negatives) it means they're parallel and congruent.  So in a rhombus IJKL the vectors IJ and LK should be the same, as should JK and IL.  That much assures a parallelogram; we check IJ and JK are congruent to complete the crowing of the rhombus.

Let's calculate these vectors:

IJ = J - I = (2,6) - (-2,3) = (2 - -2, 6 - 3) = (4, 3)

LK = K - L = (7, 6) - (3, 3) = (4, 3)

IJ = LK, so far so good

(Note: If you haven't got to vectors yet you can just show the two sides are the same length, 5, and have the same slope, 3/4, both of which can be read off the vectors.)

JK = K - J = (7,6) - (2,6) = (5,0)

IL = L - I = (3, 3) - (-2, 3)  = (5, 0)

Those are the same too.    

Now we have to show IJ ≅ JK

The length of IJ is the cliche √4²+3² = 5, the same as JK, so IJ ≅ JK

We showed all four sides are congruent and we have two pair of parallel sides, so we have a rhombus.

8 0
3 years ago
Write an equation of the line passing theough the point (4,-1) and perpendicular to the line y=2x-5.
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7 0
3 years ago
A cone has a base with a radius of 9 mm and a height of 13 mm. What is the volume of the cone?
avanturin [10]

\huge\underline{\red{A}\blue{n}\pink{s}\purple{w}\orange{e}\green{r} -}

  • Given - <u>a </u><u>cone </u><u>with </u><u>base </u><u>radius </u><u>9</u><u>m</u><u>m</u><u> </u><u>and </u><u>height </u><u>1</u><u>3</u><u> </u><u>mm</u>

  • To calculate - <u>volume </u><u>of </u><u>the </u><u>cone</u>

We know that ,

Volume \: of \: cone =  \frac{1}{3}\pi \: r {}^{2}  h \\

<u>su</u><u>b</u><u>stituting </u><u>the </u><u>values</u><u> </u><u>in </u><u>the </u><u>formula</u><u> </u><u>,</u>

Volume =  \frac{1}{3}  \times  3.14  \times 9 \times 9 \times 13 \\  \\  \implies \: 1.05 \times 81 \times 13 \\  \\ \implies \: 1105.65 \: mm {}^{3}

hope helpful ~

7 0
2 years ago
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