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mihalych1998 [28]
4 years ago
13

Three teachers equally shared StartFraction 4 Over 5 EndFraction of a flat of paper that was donated to the school. What fractio

n of the flat of paper did each teacher receive?
Mathematics
2 answers:
zhannawk [14.2K]4 years ago
5 0

Answer:

B. 4/15 of the flat

Step-by-step explanation:

UNO [17]4 years ago
4 0

Answer:

(4/5) / 3 =

4/5 * 1/3 =

4/15 <== each teacher received 4/15 of a flat

Step-by-step explanation:

so B.

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Vitek1552 [10]

Answer:

y=-2\,(x-6)^2+246

with the video game cost of x = $6

This agrees with the last option in the list of possible answers

Step-by-step explanation:

Recall that the maximum of a parabola resides at its vertex. So let's find the x and y position of that vertex, by using first the fact that the x value of the vertex of a parabola of general form:

y=ax^2+bx+c

is given by:

x_{vertex}=\frac{-b}{2\,a}

In our case, the quadratic expression that generates the parabola is:

y=-2x^2+24x+174

then the x-position of its vertex is:

x_{vertex}=\frac{-b}{2\,a}\\x_{vertex}=\frac{-24}{2\,(-2)}\\x_{vertex}=\frac{-24}{-4)}\\x_{vertex}=6

This is the price of the video game that produces the maximum profit (x = $6). Now let's find the y-position of the vertex using the actual equation for this value of x:

y=-2x^2+24x+174\\y_{vertex}=-2\,(6)^2+24\,(6)+174\\y_{vertex}=-72+144+174\\y_{vertex}=246

This value is the highest weekly profit (y = $246).

Now, recall that we can write the equation of the parabola in what is called "vertex form" using the actual values of the vertex position (x_{vertex},y_{vertex}):

y-y_{vertex}=a\,(x-x_{vertex})^2\\y-246=-2\,(x-6)^2\\y=-2\,(x-6)^2+246

Therefore the answer is:

y=-2\,(x-6)^2+246

with the video game cost of x = $6

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The run is 4 .

The slope of the line is 3/4

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Looking at this, slope seems to be 2 for the graph

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