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MariettaO [177]
3 years ago
10

WILL MARK BRAINLYEST.

Mathematics
1 answer:
gtnhenbr [62]3 years ago
8 0

Answer:

1) The straight line on the graph below intercepts the two coordinate axes. The point where the line crosses the x-axis is called the [x-intercept]. The [y-intercept] is the point where the line crosses the y-axis. Notice that the y-intercept occurs where x = 0, and the x-intercept occurs where y = 0.

2) There's another important value associated with graphing a line on the coordinate plane. It's called the "y intercept" and it's the y value of the point where the line intersects the y- axis. For this line, the y-intercept is "negative 1." ... This point will always have an x coordinate of zero.

Step-by-step explanation:


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What are the steps to find (2+2i)(5+3i)?
WITCHER [35]

(2+2i)(5+3i)
10+6i+10i+6i^2
10+16i+6(-1)
4+16i
When you have an “i^2”, you also have a negative one. The simplified answer is 4+16i
6 0
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Which equation results from adding the equations in this system?
MArishka [77]

Answer:

8y = -6

Step-by-step explanation:

x + 6y -x +2y = 9 +(-15) ➡ 8y = -6

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what is 12/3 as an improper fraction? a. 2/3 b. 5/3 c. 8/3 d. 6/3 user: what is 20 × 6? a. 100 b. 40 c. 12 d. 120
Sedbober [7]
1\dfrac{2}{3}=\dfrac{1\cdot3+2}{3}=\boxed{\dfrac{5}{3}}\to\fbox{b.}\\\\20\times6=6\cdot(2\cdot10)=6\cdot2\cdot10=12\cdot10=\boxed{120}\to\fbox{d.}
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three times the lesser of two consecutive even integers is 6 less than six times the greatest number. find the integers.
kakasveta [241]

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3 0
3 years ago
What is the equation of the line that is perpendicular to the given line and has an x-intercept of -3?
Anvisha [2.4K]

Answer:

y=-\frac{3}{2}x-\frac{9}{2}

Step-by-step explanation:

Let the equation of the perpendicular line is,

y = mx + b

where m = slope of the line

b = y-intercept

From the graph, slope of the line passing through (0, -1) and (3, 1),

m' = \frac{y_2-y_1}{x_2-x_1}

m' = \frac{1+1}{3-0}

m' = \frac{2}{3}

To get the slope (m) of this line we will use the property of perpendicular lines,

m × m' = (-1)

m × \frac{2}{3} = -1

m = -\frac{3}{2}

Equation of the perpendicular line will be,

y=-\frac{3}{2}x+b

x-intercept of the line is (-3) therefore, point on the line is (-3, 0)

0 = -\frac{3}{2}(-3)+b

b = -\frac{9}{2}=-4.5

Equation of the line will be,

y=-\frac{3}{2}x-\frac{9}{2}

3 0
3 years ago
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