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Darya [45]
3 years ago
8

How can you tell that 7.630 and 7.63 are equivalent decimals?

Mathematics
2 answers:
nataly862011 [7]3 years ago
8 0
Because an equivalent decimal names the same amount as another decimal.  the 0 has no value
Diano4ka-milaya [45]3 years ago
4 0

Answer:

Two numbers are said to be equivalent or equal if after altering the number in any way possible the two numbers are same.

Here in Number ,1.---7.630 and 2.-- 7.63 ,<u>in 7.630</u>, 0 have been removed to obtain 7.63 which does not affect the numerical value of both the numbers.Also,

  1.\rightarrow7.630=\frac{7630}{1000}\\\\=\frac{763}{100}\\\\=7.63\\\\=\text{Number 2}

So, With Conformity we can say that these two numbers are equivalent.

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Step-by-step explanation:

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Graph a line that contains the point -6,1 and has a slope of 5
Stells [14]

Answer:

y=5x+31

Step-by-step explanation:

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31=b

y=5x+31

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7 0
3 years ago
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Answer:

x^7 + 9x^2 + x + 8  

Step-by-step explanation:

Combine like terms

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2 years ago
There are 50 chairs in the auditorium. 15 of the chairs are red and the rest are blue. What is the ratio of the number of blue c
navik [9.2K]

Answer: 7:3

Step-by-step explanation:

15 chairs are red

35 are blue

35:15

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7:3

7 0
2 years ago
A candidate for a US Representative seat from Indiana hires a polling firm to gauge her percentage of support among voters in he
UkoKoshka [18]

Answer:

a) The minimum sample size is 601.

b) The minimum sample size is 2401.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

The margin of error is:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

For this problem, we have that:

We dont know the true proportion, so we use \pi = 0.5, which is when we are are going to need the largest sample size.

95% confidence level

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

a. If a 95% confidence interval with a margin of error of no more than 0.04 is desired, give a close estimate of the minimum sample size that will guarantee that the desired margin of error is achieved. (Remember to round up any result, if necessary.)

This is n for which M = 0.04. So

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.04 = 1.96\sqrt{\frac{0.5*0.5}{n}}

0.04\sqrt{n} = 1.96*0.5

\sqrt{n} = \frac{1.96*0.5}{0.04}

(\sqrt{n})^2 = (\frac{1.96*0.5}{0.04})^2

n = 600.25

Rounding up

The minimum sample size is 601.

b. If a 95% confidence interval with a margin of error of no more than 0.02 is desired, give a close estimate of the minimum sample size necessary to achieve the desired margin of error.

Now we want n for which M = 0.02. So

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.02 = 1.96\sqrt{\frac{0.5*0.5}{n}}

0.02\sqrt{n} = 1.96*0.5

\sqrt{n} = \frac{1.96*0.5}{0.02}

(\sqrt{n})^2 = (\frac{1.96*0.5}{0.02})^2

n = 2401

The minimum sample size is 2401.

4 0
3 years ago
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