Let A=(0,0)(x₁,x₂), B=(6,0)(x₂,y₂) and C=(0,6)(x₃,y₃)
Centroid of ΔABC is given by,
G(x,y) = [x₁+x₂+x₃/3 , y₁+y₂+y₃/3] = [0+6+0/3 , 0+0+6/3] = [2,2]
1, 3, and 5 would be my best guesses but I’m not 100 percent sure
Answer: 14 feet 4 inches
Step-by-step explanation:
Given: The length of the first table = 7 feet 7 inches
The length of the second table = 6 feet 9 inches
The total length of two tables = 7 feet 7 inches + 6 feet 9 inches
= (7+6) feet (7+9) inches
=13 feet 16 inches
Since 1 feet = 12 inches
The total length of two tables = 13 feet+ (12 inches +4 inches)
=13 feet +( 1 feet +4 inches)
= 14 feet 4 inches
Hence, the total length of the two tables = 14 feet 4 inches
The third table on the top row. It has a linear function because the Y is always constant. For example: -3 + -2= -5 -5 + -2= -7
The solution of x is x = 0, x =2 and x = -5
<h3>How to solve for the unknown?</h3>
The equation is given as:
2x^3+6x^2-20x=0
Factor out x
x(2x^2+6x-20)=0
Split the equation
x = 0 or 2x^2+6x - 20=0
Solve for x in 2x^2+6x - 20=0
Expand the equation
2x^2 + 10x - 4x - 20 = 0
Factorize the equation
(2x - 4)(x +5) = 0
Split the equation
2x - 4 = 0 and x + 5 = 0
Solve for x
x =2 and x = -5
Hence, the solution of x is x = 0, x =2 and x = -5
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