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4 years ago

What is the unit rate of $48 for 3 pairs of shoes?

Mathematics

2 answers:

Shtirlitz [24]4 years ago

8 0

16, to find the total of one pair of shoes you have to divide the amount of $ by the pairs of shoes

forsale [732]4 years ago

7 0

Answer:

$16

Step-by-step explanation:

48÷3= $16 per pair of shoe

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How can you use a right angle to determine the classification of another angle?

nirvana33 [79]

you can measure the first angle with a protractor and then measure the other one see if there is a different angle

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3 years ago

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What percent of 78 is 16?

Phantasy [73]

Answer:

78/16=

39/8=

19.5/4= 4.80805

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3 years ago

Please can u give me this answer ☹️

Jlenok [28]

Answer:

the second one

Step-by-step explanation:

Hello There!

The area of a triangle can be found using this formula

$A = \frac{1}{2} (a+b)h$

where a and b = bases and h = height

The trapezoid shown has the following dimensions

top base = 9cm

bottom base = 14 cm

height = 12 cm

slant height = 13 cm

using this information, we plug in the values into the formula

So $A = \frac{1}{2} (9+14)12$

the equation we created matches the 2nd equation therefore the second one is your answer

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3 years ago

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the height of a triangle is 4 meters less than the base. if the area of the triangle is 6 m^2 what is the height of the triangle

inna [77]

Answer:

$2m$

Step-by-step explanation:

Alrighty let's do this.

We know that formula for the Area of a triangle is:

$A = \frac{1}{2}bh$

They give us the area as $6m^2$ , so let's include it in the equation.

$6 = \frac{1}{2}bh$

Now we reach a stage where we have 2 unknown variables! That means we can't solve it in its current state. So the idea you should have in cases like these where you have 2 or more unknown variables is, "Can I represent this one variable in terms of another variable?" In this case you can do exactly that. You can represent height in terms of length of the base. We are told the height of the triangle is 4 meters less than the base. That is telling us that $h = b-4$

So replace $h$ in the equation with $b-4$ .

You will now get:

$6 = \frac{1}{2}b(b-4)$

Now we can work towards solving. Let's get simplifying.

$12 = b(b-4)\\12 = b^2 - 4b\\$

bring everything to one side so we can make a quadratic and factor:

$0 = b^2 - 4b - 12\\0 = (b-6)(b+2)\\\\b = 6\\b\neq -2$

We get that $b=6$ .

Since we need the height of the triangle we'll need to call back on what h is. We found earlier that $h = b - 4$ , so to find h, we just sub in our b value into that.

$h = (6) - 4 = 2$

We find that $h=2$

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2 years ago

Solve the equation on the interval [0, 2pi): 12cos^2 x-9=0<br><br><br> What to do?

siniylev [52]

Answer:

$\large\boxed{x=\dfrac{\pi}{6}\ \vee\ x=\dfrac{5\pi}{6}\ \vee\ x=\dfrac{7\pi}{6}\ \vee\ x=\dfrac{11\pi}{6}}$

Step-by-step explanation:

$12\cos^2x-9=0\qquad\text{add 9 to both sides}\\\\12\cos^2x=9\qquad\text{divide both sides by 12}\\\\\cos^2x=\dfrac{9}{12}\\\\\cos^2x=\dfrac{9:3}{12:3}\\\\\cos^2x=\dfrac{3}{4}\to\cos x=\pm\sqrt{\dfrac{3}{4}}\\\\\cos x=\pm\dfrac{\sqrt3}{2}\\\\\text{Look at the picture}\\\\x=\dfrac{\pi}{6}\ \vee\ x=\dfrac{5\pi}{6}\ \vee\ x=\dfrac{7\pi}{6}\ \vee\ x=\dfrac{11\pi}{6}$

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3 years ago