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3 years ago

If 2/6=x/21 then what does x equal

Mathematics

2 answers:

Rus_ich [418]3 years ago

8 0

I got wrong in the first, sorry but this one is better

$\frac{2}{6} = \frac{x}{21} \\6x = 2 * 21\\6x = 42 \\\frac{6x}{6} = \frac{42}{6} \\x = 42$

mario62 [17]3 years ago

3 0

Answer:

x=7

Step-by-step explanation:

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tax on the original price of a bicycle is charged at 20% of the original price. After tax has been included, Mathew pays $1080 f

kicyunya [14]

Answer:

Original price of bicycle = $864

Step-by-step explanation:

Given:

Rate of tax = 20%

Price pay by Mathew = $1,080

Find:

Original price of bicycle

Computation:

Original price of bicycle = Price pay by Mathew[1 / (1-20%)]

Original price of bicycle = 1,080[1 / (1-20%)]

Original price of bicycle = 1,080[1 / (1-0.2)]

Original price of bicycle = 1,080[1 / (0.8)]

Original price of bicycle = 1,080[1.25]

Original price of bicycle = $864

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3 years ago

Sarah bought a $320000 house. She pays 20% down and takes out a 30-year loan for the rest. How much is the loan amount going to

lana [24]

The first thing you do is mutitpy 320,000 by .20 so that you can find the amount of down payment. The down payment would be 64,000. So you subtract 64,000 from 320,000. This leaves a loan amount of 256,000 dollars. The answer is 256,000 dollars .

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4 years ago

The mean age of swimers for all of these teams is 10. what does a large mad tell you.eade help

aev [14]

Answer: Larger the MAD tells us that the ages of swimmer are far from the mean age. Thus means is not a relevant indicator for the data.
Step-by-step explanation:
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3 years ago

3y''-6y'+6y=e*x sexcx

Simora [160]

From the homogeneous part of the ODE, we can get two fundamental solutions. The characteristic equation is

$3r^2-6r+6=0\iff r^2-2r+2=0$

which has roots at $r=1\pm i$ . This admits the two fundamental solutions

$y_1=e^x\cos x$
$y_2=e^x\sin x$

The particular solution is easiest to obtain via variation of parameters. We're looking for a solution of the form

$y_p=u_1y_1+u_2y_2$

where

$u_1=-\displaystyle\frac13\int\frac{y_2e^x\sec x}{W(y_1,y_2)}\,\mathrm dx$
$u_2=\displaystyle\frac13\int\frac{y_1e^x\sec x}{W(y_1,y_2)}\,\mathrm dx$

and $W(y_1,y_2)$ is the Wronskian of the fundamental solutions. We have

$W(e^x\cos x,e^x\sin x)=\begin{vmatrix}e^x\cos x&e^x\sin x\\e^x(\cos x-\sin x)&e^x(\cos x+\sin x)\end{vmatrix}=e^{2x}$

and so

$u_1=-\displaystyle\frac13\int\frac{e^{2x}\sin x\sec x}{e^{2x}}\,\mathrm dx=-\int\tan x\,\mathrm dx$
$u_1=\dfrac13\ln|\cos x|$

$u_2=\displaystyle\frac13\int\frac{e^{2x}\cos x\sec x}{e^{2x}}\,\mathrm dx=\int\mathrm dx$
$u_2=\dfrac13x$

Therefore the particular solution is

$y_p=\dfrac13e^x\cos x\ln|\cos x|+\dfrac13xe^x\sin x$

so that the general solution to the ODE is

$y=C_1e^x\cos x+C_2e^x\sin x+\dfrac13e^x\cos x\ln|\cos x|+\dfrac13xe^x\sin x$

7 0

3 years ago

Which of the following best describes the surface area of a solid figure?

grandymaker [24]

Assuming the figure has identifiable bases and sides, the total surface area is the sum of the areas of those:

... B. Base area + lateral area

4 0

3 years ago

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