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sukhopar [10]
3 years ago
15

A plane leaves Texas. It arrives in London 10 hours later.what time did it leave Texas

Mathematics
2 answers:
tankabanditka [31]3 years ago
5 0
10 hours before it left?
GenaCL600 [577]3 years ago
5 0
The correct answer is: 10 hours before it left
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What is the value of x ​
attashe74 [19]

Answer:

the answer is 82° because if u added 45+53+82 it would come out to be 180° which is the overall degrees of a triangle.

5 0
3 years ago
A raffle offers a first prize of $1000, 2 second prizes of $300, and 20 third prizes of $10 each. If 20000 tickets are sold at 2
Shalnov [3]

Answer:

The expected winnings for a person buying 1 ticket is -0.2.                  

Step-by-step explanation:

Given : A raffle offers a first prize of $1000, 2 second prizes of $300, and 20 third prizes of $10 each. If 20000 tickets are sold at 25 cents each, find the expected winnings for a person buying 1 ticket.

To find : What are the expected winnings?    

Solution :

There are one first prize, 2 second prize and 20 third prizes.

Probability of getting first prize is \frac{1}{20000}

Probability of getting second prize is \frac{2}{20000}

Probability of getting third prize is \frac{20}{20000}

A raffle offers a first prize of $1000, 2 second prizes of $300, and 20 third prizes of $10 each.

So, The value of prizes is

\frac{1}{20000}\times 1000+\frac{2}{20000}\times 300+\frac{20}{20000}\times 10

If 20000 tickets are sold at 25 cents each i.e. $0.25.

Remaining tickets = 20000-1-2-20=19977

Probability of getting remaining tickets is \frac{19977}{20000}

The expected value is

E=\frac{1}{20000}\times 1000+\frac{2}{20000}\times 300+\frac{20}{20000}\times 10-\frac{19977}{20000}\times 0.25

E=\frac{1000+600+200-4994.25}{20000}

E=\frac{-3194.25}{20000}

E=-0.159

Therefore, The expected winnings for a person buying 1 ticket is -0.2.

3 0
3 years ago
For each function, what is the output of the given input? for f(x) = 4x 7, find f(4)
shusha [124]
I hope this helps you




x =4



f (4)= 4.4+7 = 16+7=23



f (4)= 4.4-7=16-7=9
6 0
3 years ago
Point J (-4, -6) and point K (4, 4) are located on a coordinate grid. Which measurement is closest to the distance between point
shepuryov [24]

Answer:

The points are sqrt(164) or 2sqrt(41) units apart.

Explanation:

You didn't provide the options in your question. But to find the distance, you need to use the distance formula.

d=sqrt((y2-y1)^2 + (x2-x1)^2)

d is the distance, and (x1, y1) and (x2, y2) are the points.

Use point J (-4,-6) for (x1,y1) and point K (4,4) for (x2, y2).

d=sqrt((4-(-6))^2 + (4-(-4))^2)

 =sqrt(10^2 + 8^2)

 =sqrt(100+64)

 =sqrt(164)=2sqrt(41)

You can compare this to the answer options and find the closest. Hope I could help! :)

3 0
3 years ago
What is the measure of angle BAC ?
Eva8 [605]
An inscribed angle (BAC) is one half the angle of a central angle (BOC) that intercepts the same arc.  Therefore, BAC = 34 degrees.


3 0
3 years ago
Read 2 more answers
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