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Novosadov [1.4K]
3 years ago
10

PLZ HELP ME WITH THIS ASAP

Mathematics
1 answer:
Softa [21]3 years ago
5 0
9. 10^42
10. 59049 x 2^36
11. 12^28
12. 1.85302019 x 10^15
13. 2^11
14. 1/2
15. -1
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HELPPPP :(((
sp2606 [1]

Answer:

9.1

Step-by-step explanation:

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3 years ago
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What the same as 1.4
liubo4ka [24]

Answer:

\frac{7}{5}

Step-by-step explanation:

You can make 1.4 as a fraction, and it will be the same but in a different form.

So, to make a decimal by a fraction, you make 1.4 into a whole number. 1.4 will be 14.

Now, the denominator will be 10.

So, when you simplify \frac{14}{10}, which is \frac{7}{5}

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3 years ago
Which expression represents the phrase the sum of twice a number and 7
bixtya [17]

Answer:

2n+7

Step-by-step explanation:

3 0
3 years ago
Show that the sum of two concave functions is concave. Is the product of two concave functions also concave?
spayn [35]

Answer with explanation:

Let us assume that the 2 functions are:

1) f(x)

2) g(x)

Now by definition of concave function we have the first derivative of the function should be strictly decreasing thus for the above 2 function we conclude that

\frac{d}{dx}\cdot f(x)

Now the sum of the 2 functions is shown below

y=f(x)+g(x)

Diffrentiating both sides with respect to 'x' we get

\frac{dy}{dx}=\frac{d}{dx}\cdot f(x)+\frac{d}{dx}\cdot g(x)\\\\

Since each term in the right of the above equation is negative thus we conclude that their sum is also negative thus

\frac{dy}{dx}

Thus the sum of the 2 functions is also a concave function.

Part 2)

The product of the 2 functions is shown below

h=f(x)\cdot g(x)

Diffrentiating both sides with respect to 'x' we get

h'=\frac{d}{dx}\cdot (f(x)\cdot g(x))\\\\h'=g(x)f'(x)+f(x)g'(x)

Now we can see the sign of the terms on the right hand side depend on the signs of the function's themselves hence we remain inconclusive about the sign of the product as a whole. Thus the product can be concave or convex.

8 0
3 years ago
(5+5i)(5-5i)=what????
Irina18 [472]
(First,Outer,Inner,Last)
25-25i+25i-25
0
3 0
3 years ago
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