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3 years ago

PLZ HELP ME WITH THIS ASAP

Mathematics

1 answer:

Softa [21]3 years ago

5 0

9. 10^42
10. 59049 x 2^36
11. 12^28
12. 1.85302019 x 10^15
13. 2^11
14. 1/2
15. -1

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Use Vieta's Theorem to solve the problems.

VladimirAG [237]

Answer:

The answer is -2, -17

Step-by-step explanation:

You write a system of equations

$x_{1} +x_{2}=-19\\x_{1}-x_{2}=15$

Then you solve:

-2, -17

4 0

3 years ago

each paperclip is 7/8 of an inch long and costs $.03. exactly enough paper clips are laid end to end yo have a total length of 5

GalinKa [24]

1 clipe..............7/8
x.......................56

7x/8 = 56
7x = 56*8
x = 56*8/7
x = 8*8
x = 64 clipes

1 clipe = 0,03
64 clipes = 0,03*64
64 clipes = 1,92

5 0

2 years ago

Kellie has 3/5 hour left to finish 6 math problems on the test how much time does she have to spend on each problem

seropon [69]

Answer:

6 minutes

Step-by-step explanation:

There are 60 minutes in an hour. This can be broken up into 5 12-minute intervals. From there, you can do 3 intervals of 12 minutes which is 36 minutes. The 36 minutes is divisible by 6 questions getting to 6 minutes per question.

8 0

2 years ago

System of Equations <br> Need help<br> Trig

Yanka [14]

Looks like the system is

$\begin{cases}-2x+y+6z=1\\3x+2y+5z=16\\7x+3y-4z=11\end{cases}$

We can eliminate $y$ by taking

$(3x+2y+5z)-2(-2x+y+6z)=16-2(1)$

$\implies3x+2y+5z+4x-2y-12z=16-2$

$\implies7x-7z=14$

$\implies x-z=2$

so that $z=x-2$ , and

$(7x+3y-4z)-3(-2x+y+6z)=11-3(1)$

$\implies7x+3y-4z+6x-3y-18z=11-3$

$\implies13x-22z=8$

Substitute $z=x-2$ into this last equation and solve for $x$ :

$13x-22(x-2)=8$

$\implies13x-22x+44=8$

$\implies-9x=-36$

$\implies x=4$

Then

$z=x-2$

$\implies z=4-2$

$\implies z=2$

Plug these values into any one of the original equation to solve for $y$ :

$-2x+y+6z=1$

$\implies-2(4)+y+6(2)=1$

$\implies-8+y+12=1$

$\implies y=-3$

Hence the solution is x = 4, y = -3, and z = 2.

6 0

3 years ago

ann is grouping 38 rocks, she can put into groups of 10 rocks or as single rocks what are the different ways she can group them

inysia [295]

Since Anna is either grouping them as single rock or as group of 10, we need to find the maximum number of groups of 10 as follows: 38/10 = 3.8

This means that Anna can make maximum 3 groups of 10 rocks.

Based on this, the different ways to group the rocks are as follows:
- 3 groups of 10 and 8 (which are calculated as: 38-30) single rocks
- 2 groups of 10 and 18 (which are calculated as: 38-20) single rocks
- 1 group of 10 and 28 (which are calculated as: 38-10) single rocks
- 0 group of 10 and 38 (which are calculated as: 38-0) single rocks

5 0

3 years ago