THat would be B
Addition Property of EQuality
Answer:
Step-by-step explanation:
As with all word problems we first have to convert it to an equation or equations.
L = length of the Rectangle and W = its width
So L = 2 * W
A = area of the rectangle which is 128 cm^2
So A = L * W = 128 cm^2
substitute 2W for L from the 1st equation to give A = 2 * W * W = 2 * W^2 = 128 cm^2
Thus W^2 = 64 cm^2
finally W = 8 cm and therefore L = 2 * W = 16 cm
The perimeter P = 2 * (L+W) = 2* (8cm + 16cm) = 2 * 24cm = 48 cm
The answer is D because if the perimeter of wxyz can be found by multiplying 2 with the perimeter of hjkl, then the area would be area of hjkl times 2
Answer:
(x-3)(x-7)
Step-by-step explanation:
