330-> -100 = 230, 230-> -100= 130
(I literally just watched a video how to do this, I never had to do it this way when I was in 2nd grade)
[130 final answer]
Rowena will be paying <span>A. $1,000 to the insurance company per year.</span>
16 = G + C
C = G - 6
16 = G + G - 6
16 = 2G - 6
22 = 2G
11 = G
G = 11
20 = B + K
B = 3K
20 = 3K + K
20 = 4K
5 = K
20 - 5 = 15
B = 15
Write the equation out: (total cost: 0.35C[per carton] + 75[delivery charge]) ≤ 500. Subtract 75 on both sides and it would be: 0.35C ≤ 425. Divide 0.35 on both sides and you'll get C ≤ 1214. Therefore, the maximum # of cartons that Elvira can buy is 1214 cartons of milk.
First you'd substitute x= y-3 in the first equation.
10(y-3) -10y= 1
10y - 30 -10y= 1
The y's cancel each other out, so you're left with -30= 1. That means there's no solution :)
