X+y+z = 132
x = 7+z
y = 3z
(7+z)+3z+z = 132
5z = 132-7
z = 125/5
z = 25 <=====
x = 7+z
x = 7 + 25
x = 39 <=====
y = 3z
y = 3 × 25
y = 75 <=====
hope it helps :)
Answer:
U just said a random thing
Step-by-step explanation:
Answer:
45
Step-by-step explanation:
15 x 12 = 180
180 divided by 4 = 45
45 x 4 = 180
(if correct plz mark brainliest)
Answer:
0.79
Step-by-step explanation:
Here,
Let X be the event that the flights depart on time
Let Y be the event that flights arrive on time
So,
X∩Y will denote the event that the flights departing on time also arrive on time.
Let P be the probability
P(X∩Y)=0.65
And
P(X)=0.82
We have to find P((Y│X)
We know that
P((Y│X)=P(X∩Y)/P(X) )
=0.65/0.82
=0.79
So the probability that a flight that departs on schedule also arrives on schedule is: 0.79
