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Anastaziya [24]
4 years ago
11

Greg has enough framing to enclose a rectangular photograph with a perimeter of 160 centimeters. If the width of his photograph

is 16 centimeters less than the length, what is the width, in centimeters, of the photograph
Mathematics
1 answer:
kotegsom [21]4 years ago
8 0

Answer:

32cm

Step-by-step explanation:

Let the width be w. Now we know that the width is 16cm less than the length, this means that the length will thus have a total length of w + 16

Now, we know that the perimeter of a rectangle is 2(l + b)

This means 2(w + w + 16) = 160

4w + 32 = 160

4w = 128

w = 128/4 = 32cm

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Greetings! Hope this helps!

Answer

7 feet

Explanation

23-16=7

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A brainliest would help tons! :D

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Is the triangle obtuse, acute, equilateral or right?
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Answer:

  obtuse

Step-by-step explanation:

The law of cosines tells you ...

  b² = a² +c² -2ac·cos(B)

Substituting for a²+c² using the given equation, we have ...

  b² = b²·cos(B)² -2ac·cos(B)

We can subtract b² to get a quadratic in standard form for cos(B).

  b²·cos(B)² -2ac·cos(B) -b² = 0

Solving this using the quadratic formula gives ...

  \cos(B)=\dfrac{-(-2ac)\pm\sqrt{(-2ac)^2-4(b^2)(-b^2)}}{2b^2}\\\\\cos(B)=\dfrac{ac}{b^2}\pm\sqrt{\left(\dfrac{ac}{b^2}\right)^2+1}

The fraction ac/b² is always positive, so the term on the right (the square root) is always greater than 1. The value of cos(B) cannot be greater than 1, so the only viable value for cos(B) is ...

  \cos(B)=\dfrac{ac}{b^2}-\sqrt{\left(\dfrac{ac}{b^2}\right)^2+1}

The value of the radical is necessarily greater than ac/b², so cos(B) is necessarily negative. When cos(B) < 0, B > 90°. The triangle is obtuse.

4 0
3 years ago
Read 2 more answers
Can you help me with this one
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5 is b and 1 is a
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And for 5
Day is x, y is depending on x and your going to add .4 to everything. But it’s growing .2 every day so it’s
Y=0.2x+0.4

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Have a nice night.
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7 0
3 years ago
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Nancy had 333 dollars to spend on 9 books. After buying them she had 18 dollars. How much did each book cost ?
MissTica

Answer:

35 dollars

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315/9=35 dollars for each book

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3 years ago
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