Answer:
D) 4.7
Step-by-step explanation:
this perpendicular connection with the circle center cuts this intersecting line in half, which is therefore on both sides of x 6.5 long.
I assume 16 is the diameter, so the radius is 8.
therefore, x is one side of the right-angled triangle of
radius
x
half of the intersecting line
Pythagoras
8² = x² + (6.5)²
64 = x² + 42.25
21.75 = x²
x = 4.7
Answer:
The walk will cost $8164.
Step-by-step explanation:
Given:
Diameter of the circular pond (D) = 24 yd
Width of the gravel path (x) = 2 yd
Cost per yard of the path = $50
Now, radius of the circular pond is half of the diameter and is given as:
Now, area of the pond is given as:
Area of the complete path including the pond area is given as:
Now, area of the gravel path can be obtained by subtracting the pond area from the total outer area. This gives,
Now, using unitary method,
Cost of 1 square yard of path = $50
∴ Cost of 163.28 square yard of path = 50 × 163.28 = $8164
Hence, the walk will cost $8164.
Answer:
the one on top= c= -12
the bottom one= f= -15
Step-by-step explanation:
Answer:
Step-by-step explanation:
1) Let the random time variable, X = 45min; mean, ∪ = 30min; standard deviation, α = 15min
By comparing P(0 ≤ Z ≤ 30)
P(Z ≤ X - ∪/α) = P(Z ≤ 45 - 30/15) = P( Z ≤ 1)
Using Table
P(0 ≤ Z ≤ 1) = 0.3413
P(Z > 1) = (0.5 - 0.3413) = 0.1537
∴ P(Z > 45) = 0.1537
2) By compering (0 ≤ Z ≤ 15) ( that is 4:15pm)
P(Z ≤ 15 - 30/15) = P(Z ≤ -1)
Using Table
P(-1 ≤ Z ≤ 0) = 0.3413
P(Z < 1) = (0.5 - 0.3413) = 0.1587
∴ P(Z < 15) = 0.1587
3) By comparing P(0 ≤ Z ≤ 60) (that is for 5:00pm)
P(Z ≤ 60 - 30/15) = P(Z ≤ 2)
Using Table
P(0 ≤ Z ≤ 1) = 0.4772
P(Z > 1) = (0.5 - 0.4772) = 0.0228
∴ P(Z > 60) = 0.0228
Answer:
7
Step-by-step explanation:
The width is smaller, so it is 7.
