1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
asambeis [7]
3 years ago
13

uppose that molecules of glucose are ingested, absorbed into the bloodstream, and then converted inside muscle cells to carbon d

ioxide, which is eliminated through the lungs. Describe the path of these molecules as they travel through the body, being sure to mention the various barriers (epithelia or cell membranes) that must be crossed.
Biology
1 answer:
Sophie [7]3 years ago
5 0

Answer:

Phase 1: Preparation, regulation and energy expenditure

In the initial preparatory phase of glycolysis (investment phase), glucose is phosphorylated twice by ATP and cleaved into two phosphate trioses. [2] At this stage, the cell spends two molecules of ATP, the Mg2 + cation is indispensable for the reactions, and five biochemical reactions are processed. No energy is stored, on the contrary, two ATP molecules are invested in phosphorylation reactions.

Reaction 1: hexokinase

In the first reaction, the glucose entering the tissues is phosphorylated to the hydroxyl group at C6, with the energy expenditure of an ATP molecule, giving rise to glucose-6-phosphate and ADP. [1] This reaction, catalyzed by the hexokinase enzyme, is irreversible under physiological conditions due to its highly negative ΔG °. It is one of the three steps that regulate glycolysis. The phosphorylation of glucose in the first reaction prevents it from leaving the cell again (glycolysis takes place in the cell's cytosol). By adding a phosphate group to glucose, it becomes a negatively charged molecule and it is impossible to passively pass through the cell membrane, keeping it trapped within the cell.

Glucose-6-phosphate is a branching point in carbohydrate metabolism. It is a precursor to almost all routes that use glucose, including glycolysis, via pentose phosphate and glycogen synthesis. From an opposite point of view, it can also be generated from other carbohydrate metabolism routes, such as glycogenolysis (glycogen breakdown), via pentose phosphate and gluconeogenesis (synthesis of glucose from non-carbohydrates).

Hexokinases, enzymes that catalyze glucose phosphorylation, are a family of tissue-specific isoenzymes that differ in their kinetic properties. The isoenzyme found in the liver and cells of the pancreas has a much higher Km than other hexokinases and is called glycokinase. Kinases are enzymes that catalyze the transfer of a terminal phosphoryl group from ATP to a nucleophile acceptor. In the case of hexokinase, the acceptor is a hexose, usually D-glucose, although hexokinase can catalyze the phosphorylation of other common hexoses, such as D-fructose and D-mannose. Hexokinase, like many other kinases, requires Mg2 + for its activity, since the true substrate of the enzyme is not ATP-4, but MgATP-2. In many cells, part of the hexokinase is bound to porins in the outer mitochondrial membrane, which give these enzymes early access to the newly synthesized ATP as it leaves the mitochondria.

Reaction 2: phosphohexose isomerase

In the second reaction, catalyzed by the enzyme glycosphosphate isomerase (also called phosphoxose isomerase), glucose-6-phosphate, an aldose, is converted into a reversible isomerization process in fructose-6-phosphate, a ketosis, thus allowing a site input for dietary fructose in glycolysis. This isomerization plays a critical role in the general chemistry of the glycolytic pathway, since the rearrangement of the carbonyl and hydroxyl groups at C-1 and C-2 is a necessary preparation for the next two steps. The phosphorylation that occurs in the next reaction (reaction 3) requires that the group at C-1 be first converted from a carbonyl to an alcohol and, in the subsequent reaction (reaction 4), the cleavage of the bridge between C-3 and C-4 by aldolase requires a carbonyl group at C-2.

Reaction 3: phosphofructokinase-1 (PFK1)

In reaction number 3, the cell invests another ATP molecule to phosphorylate fructose-6-phosphate and convert it to fructose-1,6-bisphosphate. This is also an irreversible and control reaction of this metabolic pathway, catalyzed by the enzyme phosphofrutokinase, which is the enzyme pacemaker of glycolysis. This step occurs to make the molecule symmetrical for the cleavage reaction in the next step.

Reaction 4: aldolase

In reaction 4, fructose-1,6-bisphosphate is cleaved into two trioses: glyceraldehyde-3-phosphate and dihydroxyacetone phosphate. This reaction is catalyzed by the enzyme aldolase.

Reaction 5: triosphosphate isomerase

Glyceraldehyde-3-phosphate and dihydroxyacetone phosphate are isomers that are easily interconnected by the enzyme triosphosphate isomerase. Then, the conversion of dihydroxy ketone P into glyceraldehyde 3P occurs, the only triosis that can continue to be oxidized.

Phase 2: ATP production and oxidation

In the ATP generation phase (yield), glyceraldehyde-3-phosphate (a phosphate triosis) is oxidized by NAD and phosphorylated using inorganic phosphate. The high-energy phosphate bridge generated in this step is transferred to the ADP to form ATP. The remaining phosphate is also rearranged to form another high-energy phosphate bridge that is transferred to the ADP. As there are two moles of phosphate triosis formed, the result

Explanation:

You might be interested in
Cancer cells can reproduce rapidly because they
Yuliya22 [10]

<u>Answer</u>:

Cancer cells can reproduce rapidly because they spend less time in interphase.

<u>Explanation</u>:

Due to the new faults in the gene and mutations cancer cell results in faster growth. And also can spread all over the body. So as become resistant to the treatments. Cancer cells avoids the signals and keep on destroying the body cells. They never undergo apoptosis when should go, so they are referred as the immortals. These cells use body’s protein and fat as fuel to undergo their processes in the absence of sugar. Excess sugar also acts as fuel for the growth of the cancer cells.

7 0
3 years ago
No links please, and thank you in advance :)
Ilya [14]

Answer:

important scientific tool used to identify different organisms, based the organism's observable traits

Explanation:

consist of a series of statements with two choices in each step that will lead users to the correct identification

For example, in tree identification, a dichotomous key might ask whether the tree has leaves or needles. The key then directs the user down one list of questions if the tree has leaves, and a different question list if it has needles.

7 0
3 years ago
Read 2 more answers
Vercuronium and rocuronium are used to
Oxana [17]

Vecuronium and rocuronium are commonly used "non-depolarizing" neuromuscular blockers (NMBs).

4 0
3 years ago
What causes variations in asexual organisms?
Nezavi [6.7K]
<span>Variations in asexual organisms are rather rare since they occur as a result of mistake of mitosis during DNA copying. On the other hand, variations in sexual organisms are a result of fusion of two different gametes that carry different traits. Thus, the offspring carries characteristics of both parents, resulting in greater genetic variation within the next generation. Consequently, sexual organism obtain greater genetic variation than asexuallt reproducing species.</span>
8 0
3 years ago
if the southern latitudes get more sun exposure for longer hours per day than Northern latitudes predict the effects on the anim
kumpel [21]

Answer:

Date and latitude interact to determine photoperiod, the daily period of daylight. This interaction has important implications for latitudinal migrants for whom daylight may be a resource or for whom photoperiod regulates annual transitions in life‐history stages (i.e. birds).

Using an established formula, we developed user‐interactive, animated models that enable the visualization of how latitude and date determine photoperiod for latitudinal migrants. We also calculated the photoperiodic schedules for a broad range of hypothetical migratory programmes and real migratory programmes newly available through the proliferation of citizen‐science data. This enabled us to infer the limitations some migratory programmes place on mechanisms for photoperiodic regulation of annual breeding.

In the vast majority of cases, the act of migrating elevates annual daylight exposure. This raises the hypothesis that daylight availability selects for latitudinal migration, potentially contributing to its evolution in animals such as diurnal birds with limited time during the spring and summer to feed young. However, photoperiodic mechanisms regulating annual cycles could constrain the evolution of such migrations, depending on how they affect photoperiodic schedules. Most migratory programmes are consistent with known mechanisms of avian photoperiodism, but the range of feasible mechanisms declines for transequatorial migrants, which experience semi‐annual, 180°‐phase‐shifts in their photoperiodic cycles.

Understanding photoperiodic constraints on migration are particularly important in this age of changing latitudinal distributions and phenologies driven by climate change.

Hope this helps and have a great day!!! :D

8 0
3 years ago
Other questions:
  • What do volcanoes have to do with the carbon cycle ?
    10·1 answer
  • Using an example (from class or another) and one of the forms of evolution, explain in a short paragraph the true scientific mea
    13·1 answer
  • If a scientist wanted to follow mendel’s experiment with a different kind of plant, which type of plant would she examine? a pla
    9·2 answers
  • What will most likely happen to a plant that doesn't receive enough c02
    12·2 answers
  • Please answer these questions.​
    14·1 answer
  • Lurray Caverns in Virginia is a cavern that formed from water moving down into limestone rock below ground and forming calcite f
    7·1 answer
  • What animal barks like a dog but flys like a Eagle and looks like a rat
    9·2 answers
  • Describe What is a theorist is
    6·1 answer
  • What are all the parts of a protist cell.
    14·1 answer
  • Whats the answer to this multiple choice?
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!