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neonofarm [45]
3 years ago
13

Point A is located at (0, 4), and point C is located at (−3, 5). Find the x value for point B that is located one over four the

distance from point A to point C. (4 points)
−0.25

−0.5

−0.75

−1
Mathematics
2 answers:
uysha [10]3 years ago
7 0
The answer is 0.25 hope this helps
Alex787 [66]3 years ago
3 0

Hi!

Answer:

C.-0.75

Step-by-step explanation:

A(0,4) C(-3,5)

distance between x-coordinates is 3

distance between y-coordinates is 1

We're asked to find point B which

is located 1/4 distance from point A to point C.

So we will take the distance of the x-coordinates and y-coordinates and multiply them by 1/4.

3 x 1/4 = 0.75

1 x 1/4 = 0.25

Now, we are looking for the x value in which point B is located, on a coordinate grid C is to the left of A, which means this is a negative movement. Thus, all we have to do is subtract 0.75 from 0 since it is negative.

0 - 0.75 = -0.75

Then that's

the x value for point B.

Hope this helped!

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What is 10x-3>3x+11 as a word problem​
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Answer:

Ten times a number minus 3 is greater than three times the number plus eleven

Step-by-step explanation:

we have the inequality

10x-3 > 3x+11

Let

x ----> a number

As a word problem will be

10x -----> Ten times a number x

+ ----> plus

-3 ----->  negative 3

> greater than

3x ----> three times a number x

11 ----> eleven

therefore

Ten times a number minus 3 is greater than three times the number plus eleven

7 0
3 years ago
A family needs to cross a river in a small raft.
serg [7]

Answer:

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Step-by-step explanation:

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Can someone please help me with this problem?
jeka57 [31]

Answer:

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Step-by-step explanation:

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D

Step-by-step explanation:

3 0
4 years ago
Sample Response: You would graph the equation f(x) = –x + 3 for input values less than 2. There would be an open circle at the p
fgiga [73]

Answer:

Step-by-step explanation:

What did you include in your response? Check all that apply.

There would be an open circle at (2, 1).  <u>Yes</u>

There would be a closed circle at (2, 3).  <u>Yes</u>

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