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neonofarm [45]
3 years ago
13

Point A is located at (0, 4), and point C is located at (−3, 5). Find the x value for point B that is located one over four the

distance from point A to point C. (4 points)
−0.25

−0.5

−0.75

−1
Mathematics
2 answers:
uysha [10]3 years ago
7 0
The answer is 0.25 hope this helps
Alex787 [66]3 years ago
3 0

Hi!

Answer:

C.-0.75

Step-by-step explanation:

A(0,4) C(-3,5)

distance between x-coordinates is 3

distance between y-coordinates is 1

We're asked to find point B which

is located 1/4 distance from point A to point C.

So we will take the distance of the x-coordinates and y-coordinates and multiply them by 1/4.

3 x 1/4 = 0.75

1 x 1/4 = 0.25

Now, we are looking for the x value in which point B is located, on a coordinate grid C is to the left of A, which means this is a negative movement. Thus, all we have to do is subtract 0.75 from 0 since it is negative.

0 - 0.75 = -0.75

Then that's

the x value for point B.

Hope this helped!

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c = f + 2

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Each time there is a new figure ( f ), two circles ( c ) are added.

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Lines p and q are parallel. What is m&lt;1?<br><br><br> 30 <br><br>66<br><br> 84 <br><br>96
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A t-shirt is launched into the stands at a game. The equation h(x) = -16x2 + 48x + 6 models the relationship between time x and
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5 0
3 years ago
16. From past experience, a company has found that in cartons of transistors, 92% contain no defective transistors, 3% contain o
Lynna [10]

Answer:

E(x)=0.15

V(x)=0.3075

S(x)=0.5545

Step-by-step explanation:

The mean of a discrete variable is calculated as:

E(x)=x_1*p(x_1)+x_2*p(x_2)+...+x_n*p(n)

where x_1,x_2,...,x_n are the values that the variable can take and p(x_1),p(x_2),...,p(x_n) are their respective probabilities.

So, if we call x the number of defective transistors in cartons, we can calculate the mean E(x) as:

E(x)=(0*0.92)+(1*0.03)+(2*0.03)+(3*0.02)=0.15

Because there are 0 defective transistor with a probability of 0.92, 1 defective transistor with a probability of 0.03, 2 defective transistors with a probability of 0.03 and 3 defective transistors with a probability of 0.01.

At the same way, the variance V(x) is calculated as:

V(x)=E(x^2)-(E(x))^2

Where E(x^2)=x_1^2*p(x_1)+x_2^2*p(x_2)+...+x_n^2*p(n)

So, the variance V(x) is equal to:

E(x^2)=(0^2*0.92)+(1^2*0.03)+(2^2*0.03)+(3^2*0.02)=0.33\\V(x)=0.33-(0.15)^2\\V(x)=0.3075

Finally, the standard deviation is calculated as:

S(x)=\sqrt{V(x)} \\S(x)=\sqrt{0.3075} \\S(x)=0.5545

8 0
3 years ago
Read 2 more answers
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