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3 years ago

Find the x- and y-intercepts for the graph of the equation: 9x-6y=3

1 answer:

5 0

<span>9x-6y=3
</span>x -intercepts y = 0, 9x = 3 then x = 1/3
y -intercepts x = 0, -6y = 3 then y = -1/2

answer
x -intercepts (1/3, 0)
y -intercepts (0, -1/2)

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The eleventh term from the end of the AP 14, 19, 24, …………., 264 is

vazorg [7]

Answer:

<h2>The eleventh term of the sequence is 64</h2>

Step-by-step explanation:

The sequence given is an arithmetic sequence

14, 19, 24, …………., 264

The nth term of an arithmetic sequence is given as;

Tn = a+(n-1)d where;

a is the first term = 14

d is the common difference = 19-14=24-19 = 5

n is the number of terms = 11(since we are to look for the eleventh term of the sequence)

substituting the given values in the formula given;

T11 = 14+(11-1)*5

T11 = 14+10(5)

T11 = 14+50

T11 = 64

The eleventh term of the sequence is 64

6 0

3 years ago

PLEASe help 30POINTS<br><br> What is the length of segment AB ?

lesya692 [45]

Answer:

$\sqrt{74}$

Step-by-step explanation:

<u>Distance between two points</u>

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

$\textsf{let}\:(x_1,y_1)=(2,-6)$

$\textsf{let}\:(x_2,y_2)=(7,1)$

$d=\textsf{length of segment AB}$

Substituting points into the distance formula and solving for d:

$\implies d=\sqrt{(7-2)^2+(1-(-6))^2}$

$\implies d=\sqrt{5^2+7^2}$

$\implies d=\sqrt{25+49}$

$\implies d=\sqrt{74}$

7 0

2 years ago

Read 2 more answers

Question 2 of 5

AlekseyPX

Given:

The different recursive formulae.

To find:

The explicit formulae for the given recursive formulae.

Solution:

The recursive formula of an arithmetic sequence is $f(n)=f(n-1)+d, f(1)=a,n\geq 2$ and the explicit formula is $f(n)=a+(n-1)d$ , where a is the first term and d is the common difference.

The recursive formula of a geometric sequence is $f(n)=rf(n-1), f(1)=a,n\geq 2$ and the explicit formula is $f(n)=ar^{n-1}$ , where a is the first term and r is the common ratio.

The first recursive formula is:

$f(1)=5$

$f(n)=f(n-1)+5$ for $n\geq 2$ .

It is the recursive formula of an arithmetic sequence with first term 5 and common difference 5. So, the explicit formula for this recursive formula is:

$f(n)=5+(n-1)(5)$

$f(n)=5+5(n-1)$

Therefore, the correct option is A, i.e., $f(n)=5+5(n-1)$ .

The second recursive formula is:

$f(1)=5$

$f(n)=3f(n-1)$ for $n\geq 2$ .

It is the recursive formula of a geometric sequence with first term 5 and common ratio 3. So, the explicit formula for this recursive formula is:

$f(n)=5(3)^{n-1}$

Therefore, the correct option is F, i.e., $f(n)=5(3)^{n-1}$ .

The third recursive formula is:

$f(1)=5$

$f(n)=f(n-1)+3$ for $n\geq 2$ .

It is the recursive formula of an arithmetic sequence with first term 5 and common difference 3. So, the explicit formula for this recursive formula is:

$f(n)=5+(n-1)(3)$