If the arc length of a sector in the unit circle is 4.2, what is the measure of the angle of the sector?

1 answer:

4 0

Bear in mind the Unit Circle is called so, because its radius is exactly 1, thus just 1 unit, the Unit Circle

anyway $\bf \theta=\cfrac{180s}{\pi r}\qquad 
\begin{cases}
\theta=\textit{central angle in degrees}\\
r=radius\\
s=\textit{length of the arc}\\
----------\\
s=4.2\\
r=1
\end{cases}\implies \theta=\cfrac{180\cdot 4.2}{1\cdot \pi }$

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docker41 [41]

V= 7x12×?
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4 0

3 years ago

For the love of God help me !! I'm desperate for it tomorrow

Eduardwww [97]

Try to relax. Your desperation has surely progressed to the point where
you're unable to think clearly, and to agonize over it any further would only
cause you more pain and frustration.
I've never seen this kind of problem before. But I arrived here in a calm state,
having just finished my dinner and spent a few minutes rubbing my dogs, and
I believe I've been able to crack the case.

Consider this: (2)^a negative power = (1/2)^the same power but positive.

So:
Whatever power (2) must be raised to, in order to reach some number 'N',
the same number 'N' can be reached by raising (1/2) to the same power
but negative.

What I just said in that paragraph was: log₂ of(N) = <em>- </em>log(base 1/2) of (N) .
I think that's the big breakthrough here.
The rest is just turning the crank.

Now let's look at the problem:

log₂(x-1) + log(base 1/2) (x-2) = log₂(x)

Subtract log₂(x) from each side:

log₂(x-1) - log₂(x) + log(base 1/2) (x-2) = 0

Subtract log(base 1/2) (x-2) from each side:

log₂(x-1) - log₂(x) = - log(base 1/2) (x-2) Notice the negative on the right.

The left side is the same as log₂[ (x-1)/x ]

==> The right side is the same as +log₂(x-2)

Now you have: log₂[ (x-1)/x ] = +log₂(x-2)

And that ugly [ log to the base of 1/2 ] is gone.

Take the antilog of each side:

(x-1)/x = x-2

Multiply each side by 'x' : x - 1 = x² - 2x

Subtract (x-1) from each side:

x² - 2x - (x-1) = 0

x² - 3x + 1 = 0

Using the quadratic equation, the solutions to that are
x = 2.618
and
x = 0.382 .

I think you have to say that <em>x=2.618</em> is the solution to the original
log problem, and 0.382 has to be discarded, because there's an
(x-2) in the original problem, and (0.382 - 2) is negative, and
there's no such thing as the log of a negative number.

There,now. Doesn't that feel better.

4 0

2 years ago

Will give 5 star, thanks, and brainliest for correct answers

algol13

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7 0

2 years ago

A passenger rode the subway 2 blocks west and then 10 south. If all the blocks are the same length what is the value of the slop

Nimfa-mama [501]

Answer:

The slope of the line is 5

Step-by-step explanation:

Great question, it is always good to ask away and get rid of any doubts that you may be having.

I have created an illustration which is attached below in order to help you understand the situation. As we are told the passenger rode the subway from point (0 , 0) to point (-2, 0). Then he rode the subway from point (-2, 0) to the final destination of point (-2 , -10). In order to find the value of the slope we need to use the slope formula which is

$Slope = \frac{y_{2}-y_{1} }{x_{2}- x_{1} }$