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kolezko [41]
3 years ago
5

If y=20 when x=8, whats the value of x when y=-2

Mathematics
1 answer:
lisabon 2012 [21]3 years ago
8 0

Answer:

x=-4/5

Step-by-step explanation:

8/20=x/-2

simplify 8/20 into 2/5

2/5=x/-2

cross product

5*x=-2*2

5x=-4

x=-4/5

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Answer:

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4 0
2 years ago
a contractor is building a new subdivision on the outside of a city. he has started work on the first street and is planning for
monitta

The equation of the location of the second street in standard form is

x + y = -6

Equation of the line:

The equation of the line represents the algebraic form of representing the set of points, which together form a line in a coordinate system.

The equation of the line can be formed with the help of the slope of the line and a point on the line.

The general form of the equation of a line with a slope m and passing through the point (x₁,y₁) is given as:

y = mx + b.

Where

m represents the slope of the line.

Given,

Point = ( -5 , -1)

Here we need to find the equation of the location.

For that, first we have to find the slope of the line,

Having two points in the format (x,y), the slope is given by the change in y divided by the change in x.

The equation of the street is parallel to the equation of the line in the graph, thus they have the same slope.

So, in street 1 the equation is

=> y =-x +1

And street 2 the equation is  

=> y =-x +b,  

solve for b by plugging in (-5,-1)

=> -1 =-(-5) +b

=> b= -1-5 = -6

=> b = -6

Now apply the value of b on the equation,

Then

=> y = -x -6

=> y + x = -6

So, the equation of the location is x + y = -6.

To know more about Equation of the line here.

brainly.com/question/2564656

#SPJ4

7 0
1 year ago
Solve This Using The Quadratic Formula: 3x^2+9x-6=0
aivan3 [116]
<h3>Therefore either  x = \frac{-3+\sqrt{17}}{2}    or,  x = \frac{-3-\sqrt{17}}{2}</h3>

Step-by-step explanation:

3x^2 +9x -6=0                                x = \frac{-b\pm\sqrt{b^2- 4ac} }{2a}

\Leftrightarrow x = \frac{-9\pm\sqrt{9^2- 4.3(-6)} }{2.3}                     here a = 3 ,b = 9 and c= -6

\Leftrightarrow x = \frac{-9\pm\sqrt{153} }{6}

\Leftrightarrow x = \frac{3(-3\pm\sqrt{17}) }{6}

\Leftrightarrow x = \frac{-3\pm\sqrt{17}}{2}

Therefore either  x = \frac{-3+\sqrt{17}}{2}    or,  x = \frac{-3-\sqrt{17}}{2}

4 0
3 years ago
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