Graph A since it crosses all 4 regions of the graph
If a coordinate has a negative x-coordinate and its y-coordinate is positive, then the point is on the 2nd quadrant.
That means that the point is left of the origin and above it.
Use the cross product to find the orthogonal vector, solve the parametric equation to see at which (t) the point + orthogonal vector intersects the plane, the distance is (t) * norm of vector
Answer:
3 divided by (1+2)=1
Step-by-step explanation:
bc u do parthensis first so 1+2 is 3 therfore if u divide 3 by 3 gives u one
