Answer:
In the most popular abroad country: 29,255 students
In the second-most one: 20,872 students
Step-by-step explanation:
Let's write the situation in an equation to help us solve this. X represents the amount of students in the second most popular country. So we know that in total, there's 50,127 students so let's make an equation that equals this. ???????=50,127. As we know, the most popular country has 8383 more students than the second one so we can write it as x+8383 and for the second most popular country, we can write it as x. We know that both of the countries students combined equal 50,127 students so we have our equation. (x)+(x+8383)=50,127 students. After solving the equation, you get x=20, 872. As we know x=the amount of students in the second most popular country which means there's 20,872 students in the second one. Additionally, for the first most popular one, the equation for the amount of students in it is x+8383 so..... 20,872+8383=Total number of students in the most popular one which is 29,255 students.
Answer:
18
Step-by-step explanation: Each side on a square its the same to the other one, so 72 divided by 4 its equal to 18
Answer:
a) ∠2 and ∠4 are a linear pair
∠4 = 115°
b) ∠2 and ∠7 are alternate exterior angles
∠7 = 65°
c) ∠2 and ∠3 are vertical angles
∠3 = 65°
Step-by-step explanation:
Linear pair : a pair of adjacent angles formed when two lines intersect. The two angles of a linear pair are always supplementary (two angles whose measures add up to 180°)
Alternate exterior angles : when two parallel lines are cut by a transversal (a line that intersects two or more other, often parallel, lines), the resulting alternate exterior angles are <u>congruent</u>.
Vertical angles : a pair of opposite angles formed by intersecting lines. Vertical angles are always <u>congruent.</u>
a) ∠2 and ∠4 are a linear pair
⇒ ∠2 +∠4 = 180
⇒ 65 + ∠4 = 180
⇒ ∠4 = 180 - 65
⇒ ∠4 = 115°
b) ∠2 and ∠7 are alternate exterior angles
⇒ ∠2 ≅ ∠7
⇒ ∠7 = 65°
c) ∠2 and ∠3 are vertical angles
⇒ ∠2 ≅ ∠3
⇒ ∠3 = 65°
So, we are given 5^8. It was happy and content. But then... we had to write it as a quotient of two exponential terms with the same base in four different ways and use negative or zero exponents and ahhhhhh!!!
... anyways...
We'll build a quotient of two exponential terms with the same base 5. Something like this:
5^a / 5^b
We need them to make 5^8 when we are done. I'll first use a zero exponent.
[1] Now, zero exponents are nice since they make things equal 1. Like 5^0 = 1. Well, obviously, 5^8 / 1 = 5^8. So, our first quotient can be:
5^8 / 5^0
Done.
[2] Let's try this on its head. This one's a little weird. Remember that negative exponents flip things upside down. So 5^-8 = 1/5^8 and 1/5^-8 = 5^8 for example. In fact... that's the answer!
5^0 / 5^-8 = 5^8
Done.
[3] Let's try to not use 0s or 8s. We can be clever and do something like this:
5^-1 / 5^-9
What the heck is that? Well, we just flip them and get:
5^-1 / 5^-9 = 5^9 / 5^1 = 5^8
Done.
[4] Can you come up with one last trick on your own? Try it!
Answer:
General Formulas and Concepts:
<u>Pre-Algebra</u>
<u>Algebra I</u>
- Terms/Coefficients
- Expand by FOIL
- Functions
- Function Notation
<u>Calculus</u>
Derivatives
Derivative Notation
Derivative Property [Multiplied Constant]: ![\displaystyle \frac{d}{dx} [cf(x)] = c \cdot f'(x)](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cfrac%7Bd%7D%7Bdx%7D%20%5Bcf%28x%29%5D%20%3D%20c%20%5Ccdot%20f%27%28x%29)
Derivative Property [Addition/Subtraction]: ![\displaystyle \frac{d}{dx}[f(x) + g(x)] = \frac{d}{dx}[f(x)] + \frac{d}{dx}[g(x)]](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cfrac%7Bd%7D%7Bdx%7D%5Bf%28x%29%20%2B%20g%28x%29%5D%20%3D%20%5Cfrac%7Bd%7D%7Bdx%7D%5Bf%28x%29%5D%20%2B%20%5Cfrac%7Bd%7D%7Bdx%7D%5Bg%28x%29%5D)
Basic Power Rule:
- f(x) = cxⁿ
- f’(x) = c·nxⁿ⁻¹
Derivative Rule [Product Rule]: ![\displaystyle \frac{d}{dx} [f(x)g(x)]=f'(x)g(x) + g'(x)f(x)](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cfrac%7Bd%7D%7Bdx%7D%20%5Bf%28x%29g%28x%29%5D%3Df%27%28x%29g%28x%29%20%2B%20g%27%28x%29f%28x%29)
Step-by-step explanation:
<u>Step 1: Define</u>
<em>Identify</em>
<em />
<em />
<em />
<u>Step 2: Differentiate</u>
- Product Rule:
 + (x^3 + 7x - 1)\frac{d}{dx}[(5x + 2)]](https://tex.z-dn.net/?f=%5Cdisplaystyle%20y%27%20%3D%20%5Cfrac%7Bd%7D%7Bdx%7D%5B%28x%5E3%20%2B%207x%20-%201%29%5D%285x%20%2B%202%29%20%2B%20%28x%5E3%20%2B%207x%20-%201%29%5Cfrac%7Bd%7D%7Bdx%7D%5B%285x%20%2B%202%29%5D)
- Basic Power Rule [Derivative Property - Addition/Subtraction]:
- Simplify:
- Expand:
- [Distributive Property] Distribute 5:
- Combine like terms:
Topic: AP Calculus AB/BC (Calculus I/I + II)
Unit: Derivatives
Book: College Calculus 10e
