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wariber [46]
4 years ago
10

Determine the hexadecimal value of a mask that can be used to complement the values of thefirst and third bits of f1ag and leave

all other bits unchanged. Determine the bit operation thatshould be used with the mask value to produce the desired result
Computers and Technology
1 answer:
Makovka662 [10]4 years ago
8 0

Answer:

Let our mask be 1010000...000. Notice that, if we apply XOR operation to any number with this mask, the first and third bits will be complemented and all other bits will be unchanged. Since for each individual bit, XOR with 0 does not change the value of bit and XOR with 1 changes the value of bit.

Explanation:

To give a hexadecimal number, we should know the number of bits in representation of number.

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Al and Bill are arguing about the performance of their sorting algorithms. Al claims that his O(N log N)-time algorithm is alway
lisabon 2012 [21]

Answer:

See in Explanation

Explanation:

All you know is that an O(n log n) algorithm is eventually (a lot) faster than an O(n^{2} ) algorithm, but for any specific value of n, you can't say anything. Indeed, the asymptotic growth of the function doesn't depend on its value on n. This means that if  f(n)=O(n^{2} ) then for all c_{1} ,....\ , c_{99}, the following function is also O(n^{2} ):

f^{'} (n)=[\ cnf(n)\  if \ n

So asymptotic notation is completely uninformative regarding the performance of algorithms on specific values of n.

You could say that functions such as f^{'}(n) are artificial and never really occur in practice. This is not quite true (you can hard-code some auxiliary information for small n, for example), but even if you consider "natural" functions, asymptotic notation doesn't help you to determine anything other than asymptotic's: consider for example n^{2} against 10^{100}n\  log \ n (such examples definitely happen in practice, for example in fast matrix multiplication).

7 0
3 years ago
When using NAND gate instead of NOR gate in SR flip-flop, Q and Q’ both become one when?
Anika [276]

Answer:

  S and R both are 0

Explanation:

A <em>0</em> at the input of a NAND gate causes its output to be <em>1</em>. There is no other logic between the output NAND gate and the S or R inputs, so both inputs 0 will make both outputs 1.

4 0
4 years ago
Each pixel includes 3 colors; Red, Green and Blue. Each color uses 8 bits to store it's intensity. How many Bytes are needed for
PtichkaEL [24]

Answer: 3 bytes

Explanation:

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One pixel will therefore have:

= 8 * 3

= 24 bits

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24 bits will therefore be:

= 24/8

= 3 bytes

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A string for sure, so answer B.

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It can help kids with stimulation and it can also help them learn more. also in case of an emergency, kids will be able to reach the authorities easier

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