Answer:
// here is code in java.
import java.util.*;
// class definition
class Solution
{
// main method of the class
public static void main (String[] args) throws java.lang.Exception
{
try{
// scanner object
Scanner s=new Scanner(System.in);
// variables
String s_name;
int s_num;
System.out.print("Please enter the name:");
// read the student name
s_name=s.nextLine();
System.out.print("Please enter the number:");
// read the student number
s_num=s.nextInt();
// print name and number 12 times
for(int i=0;i<12;i++)
{
System.out.println(s_name+"----"+s_num);
}
}catch(Exception ex){
return;}
}
}
Explanation:
Create a scanner class object to read input from user.Read the student name and the number from user and assign them to variable "s_name" and "s_num".Print the student name and number 12 times with the help of for loop.
Output:
Please enter the name:Mary Kaur
Please enter the number:123456
Mary Kaur----123456
Mary Kaur----123456
Mary Kaur----123456
Mary Kaur----123456
Mary Kaur----123456
Mary Kaur----123456
Mary Kaur----123456
Mary Kaur----123456
Mary Kaur----123456
Mary Kaur----123456
Mary Kaur----123456
Mary Kaur----123456
Answer:
jointly
Explanation:
Because Hardware and Soft ware have to JOIN together to make something work
I hope i helped!
The full word of the abbeviation OS?
It is Operating System. Like Apple's OS or Microsoft's OS.
Answer:
The explanation for the question is given in the Explanation section below.
Explanation:
Throughout the query, we gave that we already have 8 core 3 GHz CMP and therefore it performs workflow in 2.0 CPI.
So,
(8 cores*3 GHz) /2.0 CPI = 12 billion/second guidance, we've turned GHz into seconds, so that's a billion years.
Well into the question considering whether he loses 6.67 L2 per 1 K direction.
So,
12*0.00667 = 80 million mistakes per second level-2. For an 8, so 32B*80 = 2560 MB per sec.
Whether the maximum storage capacity is double that of high as 2560*2 = 5120 MB per sec.
However, that's just throughout the DDR2-67 DIMM range. So, we should infer this, because only one storage source could be enough.
The variable 10 ~ 810 would equal off to 10 leaving 40 left over..
