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bulgar [2K]
3 years ago
14

What is the range of values that a short can represent?

Computers and Technology
1 answer:
ikadub [295]3 years ago
3 0

Answer:

c. Math.pow(-2.0,15.0) to (Math.pow(2.0,15.0) -1).

Explanation:

short represents a 16-bit signed integer. short is used to save memory because it occupies less space than integers where integers occupy 4 bytes short occupies 2 bytes.

Since it is signed so first bit is used to represent the sign if 0 then positive and 1 then the integer is negative.We are left with 15 bits.

So the range is -2¹⁵ to 2¹⁵-1.

Hence the answer is option c.

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Circuit-switched networks provide connection between two parties that: Group of answer choices is dedicated for use by the parti
loris [4]

Answer:

The answer is "The first choice"

Explanation:

The circuit switches are used to provide a network that connects among the two parties, which are dedicated for the use to the parties for the length of the connection. It is a familiar technique, that is used to create a network for communication, which is used on telecalls. It also enables the hardware and circuits to share among the users, and for every user, it has direct access to the circuit during the use of the network.

7 0
2 years ago
What did major networks do to combat audience erosion in the 1990s?
S_A_V [24]

Answer: I think is 3. They acquired cable channels. They acquired cable operators.

Explanation:

6 0
3 years ago
Which is true about POP3 and IMAP for incoming email?
IceJOKER [234]
<h2>Answer:</h2>

Option A: Both POP3 and IMAP  keep email on an email server by default.

is the correct answer.

<h2>Explanation:</h2>

Following points will make the idea of POP3 and IMAP clear:

<h3>POP3:</h3>
  • POP3  is the acronym for Post Office Protocol 3.
  • POP3 is the method of receiving emails in which the emails received on the app can be downloaded on to the computer by having an internet connection.
  • These downloaded emails can be viewed offline whenever needed and managed as well.
  • POP3 makes it possible that the storage space of the default server do not run short as the downloaded emails are deleted from the server.
<h3>IMAP:</h3>
  • IMAP stands for Internet Message Access Protocol.
  • It is the method in which the mails are viewed and managed directly on the internet server instead of downloading them on the computer.
  • IMAP makes sure to manage the mails so carefully and timely so that unimportant mails are deleted to make sure that the storage space does not run short.
<h3>Conclusion:</h3>

So from these points we can make sure that both ways keep emails on email server but POP3 have option to download mails from server while IMAP dont have.

<h2>I hope it will help you!</h2>
8 0
3 years ago
A computer retail store has 15 personal computers in stock. A buyer wants to purchase 3 of them. Unknown to either the retail st
Dima020 [189]

Answer:

a. 1365 ways

b. Probability = 0.4096

c. Probability = 0.5904

Explanation:

Given

PCs = 15

Purchase = 3

Solving (a): Ways to select 4 computers out of 15, we make use of Combination formula as follows;

^nC_r = \frac{n!}{(n-r)!r!}

Where n = 15\ and\ r = 4

^{15}C_4 = \frac{15!}{(15-4)!4!}

^{15}C_4 = \frac{15!}{11!4!}

^{15}C_4 = \frac{15 * 14 * 13 * 12 * 11!}{11! * 4 * 3 * 2 * 1}

^{15}C_4 = \frac{15 * 14 * 13 * 12}{4 * 3 * 2 * 1}

^{15}C_4 = \frac{32760}{24}

^{15}C_4 = 1365

<em>Hence, there are 1365 ways </em>

Solving (b): The probability that exactly 1 will be defective (from the selected 4)

First, we calculate the probability of a PC being defective (p) and probability of a PC not being defective (q)

<em>From the given parameters; 3 out of 15 is detective;</em>

So;

p = 3/15

p = 0.2

q = 1 - p

q = 1 - 0.2

q = 0.8

Solving further using binomial;

(p + q)^n = p^n + ^nC_1p^{n-1}q + ^nC_2p^{n-2}q^2 + .....+q^n

Where n = 4

For the probability that exactly 1 out of 4 will be defective, we make use of

Probability =  ^nC_3pq^3

Substitute 4 for n, 0.2 for p and 0.8 for q

Probability =  ^4C_3 * 0.2 * 0.8^3

Probability =  \frac{4!}{3!1!} * 0.2 * 0.8^3

Probability = 4 * 0.2 * 0.8^3

Probability = 0.4096

Solving (c): Probability that at least one is defective;

In probability, opposite probability sums to 1;

Hence;

<em>Probability that at least one is defective + Probability that at none is defective = 1</em>

Probability that none is defective is calculated as thus;

Probability =  q^n

Substitute 4 for n and 0.8 for q

Probability =  0.8^4

Probability = 0.4096

Substitute 0.4096 for Probability that at none is defective

Probability that at least one is defective + 0.4096= 1

Collect Like Terms

Probability = 1 - 0.4096

Probability = 0.5904

8 0
3 years ago
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