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Wewaii [24]
2 years ago
11

What is the equivalent fraction for 0.3333

Mathematics
1 answer:
lorasvet [3.4K]2 years ago
6 0
0.3333 = 1/3

Answer would be: 1/3
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Consider the sequence {4,6,8,10,...} find the 130th term of the sequence
Olin [163]

262

Step-by-step explanation:

Step 1:

To find the nth term of a sequence the basic formula is

Sn = (n*d) + (a-d)

Whereas

Sn= nth Term

n= Term to be found

d= Difference between the terms in the sequence

a= First term in the sequence

Step 2:

Sn = (130*2) +(4-2)

= 260+2

Sn= 262

The nth term for the given problem is 262

3 0
3 years ago
The difference between x and 4 is greater than 14.
VikaD [51]

Answer:

the answer is any number above 18

3 0
3 years ago
Read 2 more answers
Can help my little bro
lisabon 2012 [21]

Answer:

$0.03

Step-by-step explanation:

chips: 7.84/16=0.49

pretzels: 12.48/24=0.52

0.52=0.49=0.03

7 0
2 years ago
According to a study conducted in one city, 35% of adults in the city have credit card debts more than $2.000. A simple random s
BabaBlast [244]

Answer:

Binomial; \mu p=87.5, \sigma p=7.542

Step-by-step explanation:

  • a distribution is said be a binomial distribution iff
  1. The probability of success of that event( let it be p) is same for every trial
  2. each trial should have 2 outcome : p or (1-p) i.e, success or failure only.
  3. there are fixed number of trials (n)
  4. the trials are independent
  • here, the trials are obviously independent ( because, one person's debt doesn't influence the other person's)
  • here n=250
  • the probability of success(0.35) is same for every trial

(35/100=0.35 is the required p here)

  • \mu_{p} =n*p=250*\frac{35}{100} =250*0.35=87.5

[since, the formula for \mu _{p} =n*p ]

  • \sigma _{p} =\sqrt{n*(p)*(1-p)} = \sqrt{250*0.35*(1-0.35)} = 7.542 ( approximately)

[since, the formula for [tex]\sigma _{p} =\sqrt{n*(p)*(1-p)}

  • therefore, it is Binomial; \mu p=87.5, \sigma p=7.542

4 0
3 years ago
A researcher is interested in determining if the more than two thirds of students would support making the Tuesday before Thanks
Yakvenalex [24]

Answer:

The null hypothesis is, {H₀}: p = 0.66, H₀: p = 0.66 .

The alternative hypothesis is, {Hₐ}: p > 0.66, Hₐ​: p > 0.66

Step-by-step explanation:

Let p represent the proportion of students who are supportive of making the day before Thanksgiving a holiday.

Since two populations are considered, the alternative hypothesis for the difference of the means of the two populations has to be stated.

The proportion of two-third students are supportive of making the day before Thanksgiving a holiday is p = 0.66 obtained as shown below:

The null hypothesis is,

{H₀}:p = 0.66, H₀​: p = 0.66

The alternative hypothesis is,

{Hₐ:p > 0.66, Ha​: p > 0.66

The null hypothesis is, {H₀}: p = 0.66, H₀: p=0.66 .

The alternative hypothesis is, {Hₐ}: p > 0.66, Hₐ​: p > 0.66

3 0
2 years ago
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