Answer:
68 plants.
Step-by-step explanation:
Let x represent the number of plants that Reuben bought from the nursery.
We have been given that Reuben bought a whole bunch of plants at the nursery the other day. Right away, five died. So number of plant left would be 
.
We are also told that then our dog dug up 2/9 of them. So number of plants left after dug-up would be 
.
Further a rabbit came and ate ½ of what was left. So number of plants left would be 
.
Since Reuben had only 7 plants left, so we will equate our expression with 7 and solve for x as:
Therefore, Reuben bought 68 plants at the nursery.
Answer:
<h2><em><u>Option</u></em><em><u> </u></em><em><u>A</u></em><em><u> </u></em><em><u>and</u></em><em><u> </u></em><em><u>C</u></em></h2>
Step-by-step explanation:
As,
Answer:
90
Step-by-step explanation:
5x – 2y + (7x – y)
Combine like terms
12x -3y
Let x = 7 and y = -2
12(7) -3(-2)
84 +6
90
Answer:
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Step-by-step explanation:
Answer:
The probability that a household has at least one of these appliances is 0.95
Step-by-step explanation:
Percentage of households having radios P(R) = 75% = 0.75
Percentage of households having electric irons P(I) = 65% = 0.65
Percentage of households having electric toasters P(T) = 55% = 0.55
Percentage of household having iron and radio P(I∩R) = 50% = 0.5
Percentage of household having radios and toasters P(R∩T) = 40% = 0.40
Percentage of household having iron and toasters P(I∩T) = 30% = 0.30
Percentage of household having all three P(I∩R∩T) = 20% = 0.20
Probability of households having at least one of the appliance can be calculated using the rule:
P(at least one of the three) = P(R) +P(I) + P(T) - P(I∩R) - P(R∩T) - P(I∩T) + P(I∩R∩T)
P(at least one of the three)=0.75 + 0.65 + 0.55 - 0.50 - 0.40 - 0.30 + 0.20 P(at least one of the three) = 0.95
The probability that a household has at least one of these appliances is 0.95
