Square root of 60 divided by square root of 5

Mathematics

1 answer:

nikitadnepr [17]3 years ago

3 0

Answer: 2√3

Step-by-step explanation: To divide √60 by √5, we simply divide the numbers that are inside the radicals.

Since the quotient of 60 divided by 5 is 12,

the square root of 60 divided by the square root of 5 is √12.

However, we can simplify the square root of 12.

The √12 breaks down into 4 · 3 and 4 breaks down into 2 · 2.

The 2's match up, so a 2 comes outside of the radical.

Since the 3 doesn't pair up, it stays inside.

So our answer is 2√3.

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Y - 4 = 5/2(x + 3)....slope here is 5/2. A perpendicular line will have a negative reciprocal slope. All that means is " flip " the slope and change the sign. So our perpendicular line will have a slope of -2/5 (see how I flipped the slope and changed the sign)

I am not sure what form u need this in...so I will write a few...

point-slope form :
y - y1 = m(x - x1)
slope(m) = -2/5
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now we sub
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y - 4 = -2/5(x + 3)
y = -2/5x - 6/5 + 4
y = -2/5x - 6/5 + 20/5
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y = -2/5x + 14/5
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