Y - 4 = 5/2(x + 3)....slope here is 5/2. A perpendicular line will have a negative reciprocal slope. All that means is " flip " the slope and change the sign. So our perpendicular line will have a slope of -2/5 (see how I flipped the slope and changed the sign)
I am not sure what form u need this in...so I will write a few...
point-slope form : y - y1 = m(x - x1) slope(m) = -2/5 (-3,4)....x1 = -3 and y1 = 4 now we sub y - 4 = -2/5(x - (-3) = y - 4 = -2/5(x + 3) <== point slope form
y - 4 = -2/5(x + 3) y = -2/5x - 6/5 + 4 y = -2/5x - 6/5 + 20/5 y = -2/5x + 14/5 <== slope intercept form
y = -2/5x + 14/5 2/5x + y = 14/5...multiply by 5 2x + 5y = 14 <== standard form
