Pls help!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Airplanes approaching the runway for landing are required to stay within the localizer (a certain distance left and right of the

Arisa [49]

Answer:

a) P(x = 0) = 64.69%

b) P(x ≥ 1) = 35.31%

c) E(x) = 0.42

d) var(x) = 0.3906

Step-by-step explanation:

The given problem can be solved using binomial distribution since:

There are n repeated trials independent of each other.
There are only two possibilities: exceedence happens or exceedence doesn't happen.
The probability of success does not change with trial to trial.

The binomial distribution is given by

P(x) = ⁿCₓ pˣ (1 - p)ⁿ⁻ˣ

Where n is the number of trials, x is the variable of interest and p is the probability of success.

For the given scenario. the six daily arrivals are the number of trials

Number of trials = n = 6

The probability of success = 7% = 0.07

a) Find the probability that on one day no planes have an exceedence.

Here we have x = 0, n = 6 and p = 0.07

P(x = 0) = ⁶C₀(0.07⁰)(1 - 0.07)⁶⁻⁰

P(x = 0) = (1)(0.07⁰)(0.93)⁶

P(x = 0) = 0.6469

P(x = 0) = 64.69%

b) Find the probability that at least 1 plane exceeds the localizer.

The probability that at least 1 plane exceeds the localizer is given by

P(x ≥ 1) = 1 - P(x < 1)

But we know that P(x < 1) = P(x = 0) so,

P(x ≥ 1) = 1 - P(x = 0)

We have already calculated P(x = 0) in part (a)

P(x ≥ 1) = 1 - 0.6469

P(x ≥ 1) = 0.3531

P(x ≥ 1) = 35.31%

c) What is the expected number of planes to exceed the localizer on any given day?

The expected number of planes to exceed the localizer is given by

E(x) = n×p

Where n is the number of trials and p is the probability of success

E(x) = 6×0.07

E(x) = 0.42

Therefore, the expected number of planes to exceed the localizer on any given day is 0.42

d) What is the variance for the number of planes to exceed the localizer on any given day?

The variance for the number of planes to exceed the localizer is given by

var(x) = n×p×q

Where n is the number of trials and p is the probability of success and q is the probability of failure.

var(x) = 6×0.07×(1 - 0.07)

var(x) = 6×0.07×(0.93)

var(x) = 0.3906

Therefore, the variance for the number of planes to exceed the localizer on any given day is 0.3906.

6 0

3 years ago

Can someone help me please id really appreciate it , i’ll give you brainliest

ozzi

Answer:

Alternate Exterior Angles Theorem

Step-by-step explanation:

By looking, we can see that they are exterior angles. Because 2 parallel lines are cut by a transversal, the angles are congruent.

4 0

3 years ago

Sara plotted the locations of the trees in a park on a coordinate grid. She plotted an oak tree which was in the middle of the p

padilas [110]

Answer: $10.2\ yards$

Step-by-step explanation:

<h3> "Sara plotted the locations of the trees in a park on a coordinate grid. She plotted an oak tree, which was in the middle of the park, at the origin. She plotted a maple tree, which was 10 yards away from the oak tree, at the point (10,0) . Then she plotted a pine tree at the point (-2.4, 5) and an apple tree at the point (7.8, 5) What is the distance, in yards, between the pine tree and the apple tree in the</h3><h3>park?"</h3>

For this exercise you need to use the following formula, which can be used for calculate the distance between two points:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

In this case, you need to find distance, in yards, between the pine tree and the apple tree in the park.

You know that pine tree is located at the point (-2.4, 5) and the apple tree is located at the point (7.8, 5).

So, you can say that:

$x_2=-2.4\\x_1=7.8\\\\y_2=5\\y_1=5$

Knowing these values, you can substitute them into the formula and then evaluate, in order to find the distance, in yards, between the pine tree and the apple tree in the park.

This is:

$d=\sqrt{(-2.4-7.8)^2+(5-5)^2}=10.2\ yards$

8 0

3 years ago

Ed wants to borrow $20,000 from a bank to open a small gym. Three banks charge different interest rates. To help decide the best

Delicious77 [7]

Answer:

First bank = $6792

City bank = $6803

Star bank = $6817

Step-by-step explanation:

The lists of banks and their annual interests rates are attached.

For first bank, since the interest is 7.5%, The total interest = 7.5% of $20000 = 0.075 × $20000 = $1500

For city bank, since the interest is 8.2%, The total interest = 8.2% of $20000 = 0.082 × $20000 = $1640

For Star bank, since the interest is 9%, The total interest = 9% of $20000 = 0.09 × $20000 = $1800

The loan plus interest for the banks annually are:

First bank = $20000 + $1500 = $21500

City bank = $20000 + $1640 = $21640

Star bank = $20000 + $1900 = $21900

The monthly payments for the banks are:

First bank = $21500 / 12 months = $1792

City bank = $21640 / 12 months = $1803

Star bank = $21800 / 12 months = $1817

Since The cost to run the gym each month is $5,000. Ed's total monthly expenses for each loan option = monthly payments + cost for each month. It is calculated as:

First bank = $5000 + $1792 = $6792

City bank = $5000 + $1803 = $6803

Star bank = $5000 + $1817 = $6817

3 0

3 years ago

Solve by any method <br> y= -7x+10<br> y= -3x+6

AnnyKZ [126]

Y=1
To get it, you use the method of substitution. So you swtich the top y by the equation of the bottom=-3x+6=-7x+10. You first add 7x to each side=4x+6=10 then you minus 6 from each side=4x=4 which is 1

4 0

3 years ago