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alekssr [168]
4 years ago
7

What is the answer to 7-10

Mathematics
1 answer:
Viefleur [7K]4 years ago
4 0

Answer:

-3

Step-by-step explanation:

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Which equation represents the following situation? The difference of three times a number
Harrizon [31]
The answer is y=-3*x .
3 0
3 years ago
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Maria is using a coordinate plane with the axes labeled only with integers. She says that the point (−0.5, 2) cannot be plotted
vodka [1.7K]

Answer:

Integers ={Positive Natuaral Number +Natural numbers having negative sign behind it+Zero}

      ={------,-3,-2,-1,0,1,2,3,..........}

→Points marked on the X and Y axis on the Coordinate Plane=Integers only

→Point to be marked on the coordinate plane =(-0.5,2)

→As, points on both X and Y axis are integers only.To mark, -0.5 , mark a line between , 0 and -1,that will be ,-0.5.

→You can mark , any terminating decimal on the number line, which is marked with integers only.

→Terminating decimals are those decimals having 2^a ,\text{or}5^b, \text{or} 2^a \times 5^b in the denominator of a fraction.

So, to plot any terminating Decimal on the coordinate plane, you have to use property of Rational Numbers ,which is, you can find infinite number of terminating Decimal between two terminating Decimal.

→Mark -0.5 between 0 and -1 on the X axis.Similarly, mark integer 2 on the Y axis.Draw a line parallel to Y axis ,passing from (-0.5,0) and line parallel to X axis passing through (0,2).The intersection of these two lines will be required point (-0.5,2).

3 0
4 years ago
Read 2 more answers
find real numbers a, b, and c so that the graph of the function y=ax^2+c contains the points (-1,6), (2,7), and (0,1)
Paraphin [41]
This gives you three simultaneous equations:

6 = a + c
7 = 4a + c
1 = c
 
<u>c = 1
</u>
<u /><u />
If c =1,

6 = a + 1
<u>a = 5
</u>
<u /><u />
This doesn't work in the second equation, so the quadratic that goes through these points is not in the form y = ax^2 + bx + c
Was there supposed to be a b in the equation?




5 0
4 years ago
Find an equation of the tangent line to the curve 2(x2+y2)2=25(x2−y2) (a lemniscate) at the point (−3,1). An equation of the tan
valina [46]

2(x^2+y^2)^2=25(x^2-y^2)

Let y=y(x), so that differentiating both sides wrt x gives

4(x^2+y^2)\left(2x+2y\dfrac{\mathrm dy}{\mathrm dx}\right)=25\left(2x-2y\dfrac{\mathrm dy}{\mathrm dx}\right)

If x=-3 and y=1, the above reduces to

40\left(-6+2\dfrac{\mathrm dy}{\mathrm dx}\right)=25\left(-6-2\dfrac{\mathrm dy}{\mathrm dx}\right)\implies\dfrac{\mathrm dy}{\mathrm dx}=\dfrac9{13}

This is the slope of the tangent line, which has equation

y-1=\dfrac9{13}(x+3)\implies\boxed{y=\dfrac{9x+40}{13}}

7 0
3 years ago
A rectangle has an area of x^2-8x-48. If the width is (x+4) find the length.
inna [77]

Answer:x-12

Step-by-step explanation:

Area=x^2-8x-48

Width=x+4

length=area/width

length=(x^2-8x-48)/(x+4)

length=((x+4)(x-12))/(x+4)

length=x-12

5 0
3 years ago
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